算法代码实现之二分法查找,C/C++实现

时间:2021-11-21 22:09:38

封装成函数:

//二分法查找
//数组a是升序的,len为数组长度
//k为待查找的整数
//如果查到有就返回对应角标,
//没有就返回-1
int search(int *a,int len, int k)
{
int lo = 0, hi = len - 1;
while (lo <= hi)
{
int m = (lo + hi) >> 1;
if (a[m] < k)
{
lo = m + 1;
}
else if (a[m] > k)
{
hi = m - 1;
}
else
{
return m;
}
}
return -1;
}

测试:

int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
int len = sizeof(a)/sizeof(int);
printf("%d\n",search(a,len,6));

输出:

6