使用jaxb（unmarshal）将xml转换为java对象

I have the following XML and I need to convert it into a java object.

我有以下XML,我需要将其转换为java对象。

<tests>
    <test-data> 
         <title>BookTitle</title> 
         <book>BookName</book> 
         <count>64018</count> 
         <test-data> 
            <title>Book title1</title> 
            <book>Book Name1</book> 
            <count>5</count> 
         </test-data> 
         <test-data> 
            <title>Book title2</title> 
            <book>Book Name3</book> 
            <count>5</count> 
         </test-data> 
         <test-data> 
            <title>Book title3</title> 
            <book>Book Name3</book> 
            <count>4</count> 
         </test-data> 
    </test-data>
</tests>

I am not sure what will be my pojo when I use JAXB to convert it.

当我使用JAXB转换它时,我不确定我的pojo是什么。

I created the following POJOs as per my understanding:

根据我的理解,我创建了以下POJO:

public class Tests {

    TestData testData;

    public TestData getTestData() {
        return testData;
    }

    public void setTestData(TestData testData) {
        this.testData = testData;
    }
}

public class TestData {
    String title;
    String book;
    String count;

    public String getTitle() {
        return title;
    }
    public void setTitle(String title) {
        this.title = title;
    }
    public String getBook() {
        return book;
    }
    public void setBook(String book) {
        this.book = book;
    }
    public String getCount() {
        return count;
    }
    public void setCount(String count) {
        this.count = count;
    }
}

Please help me. Thanks in advance.

请帮帮我。提前致谢。

1 个解决方案

#1

120

Tests

On the Tests class we will add an @XmlRootElement annotation. Doing this will let your JAXB implementation know that when a document starts with this element that it should instantiate this class. JAXB is configuration by exception, this means you only need to add annotations where your mapping differs from the default. Since the testData property differs from the default mapping we will use the @XmlElement annotation. You may find the following tutorial helpful: http://wiki.eclipse.org/EclipseLink/Examples/MOXy/GettingStarted

在Tests类中,我们将添加一个@XmlRootElement注释。执行此操作将使您的JAXB实现知道当文档以此元素开头时,它应该实例化此类。 JAXB是异常配置,这意味着您只需添加注释与默认值不同的注释。由于testData属性与默认映射不同,因此我们将使用@XmlElement批注。您可能会发现以下教程很有用:http://wiki.eclipse.org/EclipseLink/Examples/MOXy/GettingStarted

package forum11221136;

import javax.xml.bind.annotation.*;

@XmlRootElement
public class Tests {

    TestData testData;

    @XmlElement(name="test-data")
    public TestData getTestData() {
        return testData;
    }

    public void setTestData(TestData testData) {
        this.testData = testData;
    }

}

TestData

On this class I used the @XmlType annotation to specify the order in which the elements should be ordered in. I added a testData property that appeared to be missing. I also used an @XmlElement annotation for the same reason as in the Tests class.

在这个类中,我使用了@XmlType注释来指定元素的排序顺序。我添加了一个似乎缺少的testData属性。我也使用了@XmlElement注释,原因与Tests类相同。

package forum11221136;

import java.util.List;
import javax.xml.bind.annotation.*;

@XmlType(propOrder={"title", "book", "count", "testData"})
public class TestData {
    String title;
    String book;
    String count;
    List<TestData> testData;

    public String getTitle() {
        return title;
    }
    public void setTitle(String title) {
        this.title = title;
    }
    public String getBook() {
        return book;
    }
    public void setBook(String book) {
        this.book = book;
    }
    public String getCount() {
        return count;
    }
    public void setCount(String count) {
        this.count = count;
    }
    @XmlElement(name="test-data")
    public List<TestData> getTestData() {
        return testData;
    }
    public void setTestData(List<TestData> testData) {
        this.testData = testData;
    }
}

Demo

Below is an example of how to use the JAXB APIs to read (unmarshal) the XML and populate your domain model and then write (marshal) the result back to XML.

下面是如何使用JAXB API读取(解组)XML并填充域模型然后将结果写入(编组)回XML的示例。

package forum11221136;

import java.io.File;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Tests.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("src/forum11221136/input.xml");
        Tests tests = (Tests) unmarshaller.unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(tests, System.out);
    }

}

#1

120