CREATE TABLE `movies`.`movie`
( `movie_id` INT(3) NULL AUTO_INCREMENT, `movie_name` VARCHAR(25) NULL,
`movie_embedded_id` VARCHAR(50) NULL, `rating_no` INT(3) NULL,
`movie_description` VARCHAR(50) NULL, PRIMARY KEY (`movie_id`(3))) ENGINE = InnoDB;
I keep getting this error:
我一直收到这个错误:
#1089 - Incorrect prefix key; the used key part isn't a string, the used length is longer than the key part, or the storage engine doesn't support unique prefix keys.
#1089 - 前缀键不正确;使用的关键部分不是字符串,使用的长度比关键部分长,或者存储引擎不支持唯一的前缀键。
but I've got no idea what it means, anyone have a clue?
但我不知道这意味着什么,任何人都有线索?
3 个解决方案
#1
70
With the part
随着部分
PRIMARY KEY (`movie_id`(3))
you are telling mysql to create a sub part key* on the first 3 Bytes of movie id. This only works for string types.
你告诉mysql在电影ID的前3个字节上创建一个子部分键*。这仅适用于字符串类型。
You need to use
你需要使用
PRIMARY KEY (`movie_id`)
without providing a length.
没有提供长度。
*Is this sure the query resulting in the error? Never saw that on a primary key, its used for indexes.
*这确定查询导致错误吗?从未在主键上看到它,它用于索引。
#2
2
after selecting PRIMARY KEY when you create table, don't input any value in pop dialog
在创建表时选择PRIMARY KEY后,不要在弹出对话框中输入任何值
#3
1
You can also get this error when creating an index if you specify a prefix length that is longer than the length of the actual column. If you tried to create an index containing someColumn(20)
but in the table someColumn is VARCHAR(15)
, then this error will occur.
如果指定的前缀长度超过实际列的长度,则在创建索引时也会出现此错误。如果您尝试创建包含someColumn(20)的索引但在表someColumn是VARCHAR(15)中,则会发生此错误。
#1
70
With the part
随着部分
PRIMARY KEY (`movie_id`(3))
you are telling mysql to create a sub part key* on the first 3 Bytes of movie id. This only works for string types.
你告诉mysql在电影ID的前3个字节上创建一个子部分键*。这仅适用于字符串类型。
You need to use
你需要使用
PRIMARY KEY (`movie_id`)
without providing a length.
没有提供长度。
*Is this sure the query resulting in the error? Never saw that on a primary key, its used for indexes.
*这确定查询导致错误吗?从未在主键上看到它,它用于索引。
#2
2
after selecting PRIMARY KEY when you create table, don't input any value in pop dialog
在创建表时选择PRIMARY KEY后,不要在弹出对话框中输入任何值
#3
1
You can also get this error when creating an index if you specify a prefix length that is longer than the length of the actual column. If you tried to create an index containing someColumn(20)
but in the table someColumn is VARCHAR(15)
, then this error will occur.
如果指定的前缀长度超过实际列的长度,则在创建索引时也会出现此错误。如果您尝试创建包含someColumn(20)的索引但在表someColumn是VARCHAR(15)中,则会发生此错误。