What would be a proper fool-proof way of doing so? I am using ASP.NET MVC 3.
这样做的适当的万无一失的方法是什么?我正在使用ASP.NET MVC 3。
5 个解决方案
#1
11
DateTime a = ...
DateTime b = ...
var ms = a.Subtract(b).TotalMilliseconds;
#2
6
(datetime2 - datetime1).TotalMilliseconds
#3
4
I'm thinking this should work. Since you asked for foolproof, I'm assuming you don't know which of the two is the later date :)
我认为这应该有效。既然你要求万无一失,我假设你不知道这两个中的哪一个是后来的日期:)
Math.Abs((date1 - date2).TotalMilliseconds)
#4
0
Subtraction would be my choice...
减法将是我的选择......
DateTime earlier = DateTime.Now;
// ...
DateTime later = DateTime.Now;
double result = (later - earlier).TotalMilliseconds;
#5
0
public static Int64 GetDifferencesBetweenTwoDate(DateTime newDate, DateTime oldDate, string type)
{
var span = newDate - oldDate;
switch (type)
{
case "tt": return (int)span.Ticks;
case "ms": return (int)span.TotalMilliseconds;
case "ss": return (int)span.TotalSeconds;
case "mm": return (int)span.TotalMinutes;
case "hh": return (int)span.TotalHours;
case "dd": return (int)span.TotalDays;
}
return 0;
}
#1
11
DateTime a = ...
DateTime b = ...
var ms = a.Subtract(b).TotalMilliseconds;
#2
6
(datetime2 - datetime1).TotalMilliseconds
#3
4
I'm thinking this should work. Since you asked for foolproof, I'm assuming you don't know which of the two is the later date :)
我认为这应该有效。既然你要求万无一失,我假设你不知道这两个中的哪一个是后来的日期:)
Math.Abs((date1 - date2).TotalMilliseconds)
#4
0
Subtraction would be my choice...
减法将是我的选择......
DateTime earlier = DateTime.Now;
// ...
DateTime later = DateTime.Now;
double result = (later - earlier).TotalMilliseconds;
#5
0
public static Int64 GetDifferencesBetweenTwoDate(DateTime newDate, DateTime oldDate, string type)
{
var span = newDate - oldDate;
switch (type)
{
case "tt": return (int)span.Ticks;
case "ms": return (int)span.TotalMilliseconds;
case "ss": return (int)span.TotalSeconds;
case "mm": return (int)span.TotalMinutes;
case "hh": return (int)span.TotalHours;
case "dd": return (int)span.TotalDays;
}
return 0;
}