使用输出从args打印出一组整数：数字为1,2,3,4,5

How do i print out a set of integers in an args array. I intend to have an output of: The numbers are 1, 2, 3, 4, 5

如何在args数组中打印出一组整数。我打算输出：数字是1,2,3,4,5

System.out.println("The numbers are ");
    for(int i=0; i< args.length;i++)
    System.out.print(args[i] + " ";

The compiler gives me an error of "i cannot be resolved to a variable" When i resolve it with "int b = 0;" it gives me a single integer, rather than the integers in args

编译器给我一个错误“我无法解析为变量”当我用“int b = 0;”解决它时它给了我一个整数，而不是args中的整数

4 个解决方案

#1

As of Java 5 you can also skip i entirely:

从Java 5开始，你也可以完全跳过我：

for( String arg : args )
   System.out.print(arg + " ");

Additionally, I'd like to advocate using curly braces even for one-statement blocks. It's easier to read and less likely to change the behavior by adding a statement (like some log statement).

另外，我想提倡使用花括号，即使是单语句块。通过添加语句（如某些日志语句）更容易阅读并且更不可能更改行为。

Example, a naive pow() method (checks skipped for simplicity):

例如，一个天真的pow（）方法（为简单而跳过检查）：

Orignal code:

原始代码：

int pow(int base, int power) { //assume power to be > 1
 int result = base;

 for( int i = 1; i <= power; i++ ) 
   result *= base;

 return result;
}

Now I'd like to log the result in each step:

现在我想在每一步中记录结果：

int pow(int base, int power) { //assume power to be > 1
  int result = base;

  for( int i = 1; i <= power; i++ ) 
    System.out.println( base + " pow( " + i + ") = " + result );
    result *= base;

  return result;
}

Suddenly, I get a wrong result for power > 2, since now result *= base; is only executed once (it is now outside the loop).

突然间，我得到一个错误的结果，因为现在结果* = base;只执行一次（它现在在循环之外）。

#2

If that is your actual code, you are missing an ending parenthesis in the last line before the semi-colon.

如果这是您的实际代码，则在分号前的最后一行中缺少结束括号。

This works for me:

这对我有用：

public class tester {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub

        System.out.println("The numbers are ");
        for (int i = 0; i < args.length; i++)
            System.out.print(args[i] + " ");
    }

}

Output (when 1 2 3 4 5 are specified on the cmd line):

输出（在cmd行上指定1 2 3 4 5时）：

The numbers are 
1 2 3 4 5

#3

Forgot parenthesis?

忘了括号？

System.out.print(args[i] + " ");

#4

You forgot to close your println method with a );.

你忘了用a）关闭你的println方法;

Your problem:

你的问题：

System.out.print(args[i] + " ";

Your solution:

你的解决方案

System.out.print(args[i] + " ");

#1