I wanted to look at only the R+G channels in an RGB image because I get better contrasts to detect an object when the Blue channel is removed. I used OpenCV to split the channels,but while merging the same after setting the blue channel to 0, my code doesn't compile.
我想只看RGB图像中的R+G通道,因为在删除蓝色通道时,我得到了更好的对比度来检测对象。我使用OpenCV来分割通道,但是当将蓝色通道设置为0时,我的代码不会被编译。
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <iostream>
using namespace cv;
using namespace std;
int main( int argc, char** argv )
{
if( argc != 2)
{
cout <<" Usage: display_image ImageToLoadAndDisplay" << endl;
return -1;
}
Mat image,fin_img;
image = imread(argv[1], CV_LOAD_IMAGE_COLOR); // Read the file
if(! image.data ) // Check for invalid input
{
cout << "Could not open or find the image" << std::endl ;
return -1;
}
namedWindow( "Display window", CV_WINDOW_AUTOSIZE );// Create a window for display.
// Show our image inside it.
// Create Windows
namedWindow("Red",1);
namedWindow("Green",1);
namedWindow("Blue",1);
// Create Matrices (make sure there is an image in input!)
Mat channel[3];
imshow( "Original Image", image );
// The actual splitting.
split(image, channel);
channel[0]=Mat::zeros(Size(image.rows, image.cols), CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,image);
imshow("R+G", image);
waitKey(0);//Wait for a keystroke in the window
return 0;
}
Could I have any feedback on where I'm going wrong? I suspect it is with setting the blue channel to 0. Is there any better way to set it to 0?Is there a way to use cvMixChannels() to do this?
我能对我的错误有任何反馈吗?我怀疑是将蓝色通道设置为0。有没有更好的方法把它设为0?是否有办法使用cvmixchannel()来完成这个任务?
4 个解决方案
#1
30
You need to change these lines
你需要改变这些线条。
channel[0]=Mat::zeros(Size(image.rows, image.cols), CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,image);
to
来
channel[0]=Mat::zeros(image.rows, image.cols, CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,3,image);
Edit
编辑
As per your comment here is the full code and result.
根据您的评论,这里是完整的代码和结果。
#include <iostream>
#include "opencv2/opencv.hpp"
#include <stdio.h>
using namespace cv;
using namespace std;
int main( int argc, char** argv )
{
if( argc != 2)
{
cout <<" Usage: display_image ImageToLoadAndDisplay" << endl;
return -1;
}
Mat image,fin_img;
image = imread("bgr.png", CV_LOAD_IMAGE_COLOR); // Read the file
if(! image.data ) // Check for invalid input
{
cout << "Could not open or find the image" << std::endl ;
return -1;
}
namedWindow( "Display window", CV_WINDOW_AUTOSIZE );// Create a window for display.
// Show our image inside it.
// Create Windows
namedWindow("Red",1);
namedWindow("Green",1);
namedWindow("Blue",1);
// Create Matrices (make sure there is an image in input!)
Mat channel[3];
imshow( "Original Image", image );
// The actual splitting.
split(image, channel);
channel[0]=Mat::zeros(image.rows, image.cols, CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,3,image);
imshow("R+G", image);
imwrite("dest.jpg",image);
waitKey(0);//Wait for a keystroke in the window
return 0;
}
Source image
源图像
Result without blue component
结果没有蓝色的组件
#2
6
Alright, I got to work using mixChannels():I have attached an addition to the code snippet above:
好的,我开始使用mixChannels():我已经附加了上面的代码片段:
Mat gr( image.rows, image.cols, CV_8UC3);
// forming an array of matrices is a quite efficient operation,
// because the matrix data is not copied, only the headers
Mat out[] = {gr};
// bgr[1] -> gr[1],
// bgr[2] -> gr[2],
int from_to[] = {1,1, 2,2 };
mixChannels( &image, 1, out, 2, from_to, 2 );
imshow("R+G",gr);
Thanks Harsha
由于Harsha
#3
6
The most efficient way to do this is without any splits and merges. This saves both time and memory.
最有效的方法是没有任何拆分和合并。这节省了时间和内存。
Just bitwise-AND your image with cv::Scalar(0,255,255)
and this will set your blue channel to zero.
只有bitwise-和你的简历的图像::标量(0,255,255),这将把你的蓝色通道设置为零。
As in: imshow("R+G", src & cv::Scalar(0,255,255));
.
如:imshow(“R + G”,src和简历::标量(0255255));。
#4
4
another way is subtracting Scalar(255,0,0)
from source image
另一种方法是从源图像中减去标量(255,0,0)。
#include <opencv2/opencv.hpp>
using namespace cv;
int main(int argc, char **argv)
{
Mat src = imread(argv[1], CV_LOAD_IMAGE_COLOR);
imshow("src", src );
src -= Scalar(255,0,0);
imshow("Green and Red channels", src );
waitKey();
return 0;
}
#1
30
You need to change these lines
你需要改变这些线条。
channel[0]=Mat::zeros(Size(image.rows, image.cols), CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,image);
to
来
channel[0]=Mat::zeros(image.rows, image.cols, CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,3,image);
Edit
编辑
As per your comment here is the full code and result.
根据您的评论,这里是完整的代码和结果。
#include <iostream>
#include "opencv2/opencv.hpp"
#include <stdio.h>
using namespace cv;
using namespace std;
int main( int argc, char** argv )
{
if( argc != 2)
{
cout <<" Usage: display_image ImageToLoadAndDisplay" << endl;
return -1;
}
Mat image,fin_img;
image = imread("bgr.png", CV_LOAD_IMAGE_COLOR); // Read the file
if(! image.data ) // Check for invalid input
{
cout << "Could not open or find the image" << std::endl ;
return -1;
}
namedWindow( "Display window", CV_WINDOW_AUTOSIZE );// Create a window for display.
// Show our image inside it.
// Create Windows
namedWindow("Red",1);
namedWindow("Green",1);
namedWindow("Blue",1);
// Create Matrices (make sure there is an image in input!)
Mat channel[3];
imshow( "Original Image", image );
// The actual splitting.
split(image, channel);
channel[0]=Mat::zeros(image.rows, image.cols, CV_8UC1);//Set blue channel to 0
//Merging red and green channels
merge(channel,3,image);
imshow("R+G", image);
imwrite("dest.jpg",image);
waitKey(0);//Wait for a keystroke in the window
return 0;
}
Source image
源图像
Result without blue component
结果没有蓝色的组件
#2
6
Alright, I got to work using mixChannels():I have attached an addition to the code snippet above:
好的,我开始使用mixChannels():我已经附加了上面的代码片段:
Mat gr( image.rows, image.cols, CV_8UC3);
// forming an array of matrices is a quite efficient operation,
// because the matrix data is not copied, only the headers
Mat out[] = {gr};
// bgr[1] -> gr[1],
// bgr[2] -> gr[2],
int from_to[] = {1,1, 2,2 };
mixChannels( &image, 1, out, 2, from_to, 2 );
imshow("R+G",gr);
Thanks Harsha
由于Harsha
#3
6
The most efficient way to do this is without any splits and merges. This saves both time and memory.
最有效的方法是没有任何拆分和合并。这节省了时间和内存。
Just bitwise-AND your image with cv::Scalar(0,255,255)
and this will set your blue channel to zero.
只有bitwise-和你的简历的图像::标量(0,255,255),这将把你的蓝色通道设置为零。
As in: imshow("R+G", src & cv::Scalar(0,255,255));
.
如:imshow(“R + G”,src和简历::标量(0255255));。
#4
4
another way is subtracting Scalar(255,0,0)
from source image
另一种方法是从源图像中减去标量(255,0,0)。
#include <opencv2/opencv.hpp>
using namespace cv;
int main(int argc, char **argv)
{
Mat src = imread(argv[1], CV_LOAD_IMAGE_COLOR);
imshow("src", src );
src -= Scalar(255,0,0);
imshow("Green and Red channels", src );
waitKey();
return 0;
}