I have a string containing a short-code which looks like the one below:
我有一个包含短代码的字符串,如下所示:
some text...
[video url="http://www.example.com/path/to/my/video.ext"]
...some more text...
I want to be able to first check if the string contains that short-code and second extract the URL from it in Java (specifically Android).
我希望能够首先检查字符串是否包含该短代码,然后再从Java中提取URL(特别是Android)。
5 个解决方案
#1
1
try as:
试着:
String str = "[video url=\"http://www.example.com/path/to/my/video.ext\"]";
if (str.contains("url=\""))
{
int indexoff = str.indexOf("url=\"");
int indexofff = str.indexOf("\"]");
String strurl = str.substring(indexoff, indexofff - indexoff);
strurl = strurl.Replace("url=\"", ""); //get url string here
}
#2
2
use this regex for checking and grabbing url:
使用此正则表达式来检查和获取URL:
\[\w+\s+url="(?<urllink>)[^"]*"\s*]
and get gorup named urllink
并获得名为urllink的gorup
#3
0
Android provides several function for this purpose. SOme of this are:
Android为此提供了多种功能。这个的原因是:
- http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
- http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
- http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
- http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
#4
0
String url = "whatever"
Boolean myBool = url.contains("ate");
String contains. Not sure what extract url means, but the string class has lots of useful functions.
字符串包含。不确定提取url的含义,但字符串类有很多有用的功能。
#5
0
A powerful and maintainable manner it to Java URL.class, then, you can mix with Regex
它是Java URL.class的一种强大且可维护的方式,然后,您可以与Regex混合使用
#1
1
try as:
试着:
String str = "[video url=\"http://www.example.com/path/to/my/video.ext\"]";
if (str.contains("url=\""))
{
int indexoff = str.indexOf("url=\"");
int indexofff = str.indexOf("\"]");
String strurl = str.substring(indexoff, indexofff - indexoff);
strurl = strurl.Replace("url=\"", ""); //get url string here
}
#2
2
use this regex for checking and grabbing url:
使用此正则表达式来检查和获取URL:
\[\w+\s+url="(?<urllink>)[^"]*"\s*]
and get gorup named urllink
并获得名为urllink的gorup
#3
0
Android provides several function for this purpose. SOme of this are:
Android为此提供了多种功能。这个的原因是:
- http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
- http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
- http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
- http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
#4
0
String url = "whatever"
Boolean myBool = url.contains("ate");
String contains. Not sure what extract url means, but the string class has lots of useful functions.
字符串包含。不确定提取url的含义,但字符串类有很多有用的功能。
#5
0
A powerful and maintainable manner it to Java URL.class, then, you can mix with Regex
它是Java URL.class的一种强大且可维护的方式,然后,您可以与Regex混合使用