The Emacs documentation has a section on character classes. According to the manual, [:digit:] should match any digit character. I've tried that using re-builder but they never match, even though [0-9] matches.
Emacs文档有一个关于字符类的部分。根据手册，[：digit：]应匹配任何数字字符。我尝试过使用重建器，但它们从不匹配，即使[0-9]匹配。
How do I use character classes in an Emacs regex?
如何在Emacs正则表达式中使用字符类？
1 个解决方案
#1
10
I figured it out. The documentation is actually explicit:
我想到了。文档实际上是明确的：
Here is a table of the classes you can use in a character alternative
下面是一个可以在字符替代中使用的类的表
So [[:digit:]] is the right way to use character classes.
所以[[：digit：]]是使用字符类的正确方法。
#1
10
I figured it out. The documentation is actually explicit:
我想到了。文档实际上是明确的：
Here is a table of the classes you can use in a character alternative
下面是一个可以在字符替代中使用的类的表
So [[:digit:]] is the right way to use character classes.
所以[[：digit：]]是使用字符类的正确方法。