I need to regex string myString to only have:
我需要regex字符串myString只有:
- 0-9
- 0 - 9
- A-Z or a-z
- a - z、a - z
- any of these characters '!#$%&'*+-/=?^_`{|}~.
- 这些角色的! # $ % & ' * +,/ = ? ^ _ { | } ~。
This is my code line:
这是我的代码行:
new Regex("[a-zA-Z0-9]").IsMatch(myString);
So far I have [a-zA-Z0-9] and this works fine for the first two listitems. Currently tearing my hair out (and it's so nice I want to keep it) over metacharacters and getting nowhere.
到目前为止，我有[a-zA-Z0-9]，这对前两个listitem很管用。现在，把我的头发剪掉(而且我想保留它)超过了元字符，而且没有得到任何地方。
Any help would be greatly appreciated. Thanks. Dave
非常感谢您的帮助。谢谢。戴夫
4 个解决方案
#1
4
Hi there If you want only the listed characters in your string it is very simple.but you need to match beginning an end of line
如果你想要字符串中列出的字符，那就很简单了。但是你需要匹配开始的底线。
new Regex("^[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]*$").IsMatch(myString);
#2
3
"[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]"
check that ("-") minus sign be the last char in a [] sequence
检查(“-”)减号是[]序列中的最后一个字符。
#3
2
Meta characters are fine between brackets, as long as you escape the significant ones. Moreover the dash MUST be the last one of your sequence.
元字符在括号之间是可以的，只要你避开了重要的字符。此外，破折号必须是你的最后一个序列。
new Regex("[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~-]").IsMatch(myString);
#4
1
Try:
试一试:
var re = "[a-zA-Z0-9" + Regex.Escape("'!#$%&'*+-/=?^_`{|}~.") + "]";
#1
4
Hi there If you want only the listed characters in your string it is very simple.but you need to match beginning an end of line
如果你想要字符串中列出的字符，那就很简单了。但是你需要匹配开始的底线。
new Regex("^[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]*$").IsMatch(myString);
#2
3
"[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]"
check that ("-") minus sign be the last char in a [] sequence
检查(“-”)减号是[]序列中的最后一个字符。
#3
2
Meta characters are fine between brackets, as long as you escape the significant ones. Moreover the dash MUST be the last one of your sequence.
元字符在括号之间是可以的，只要你避开了重要的字符。此外，破折号必须是你的最后一个序列。
new Regex("[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~-]").IsMatch(myString);
#4
1
Try:
试一试:
var re = "[a-zA-Z0-9" + Regex.Escape("'!#$%&'*+-/=?^_`{|}~.") + "]";