servlet页面跳转多次传参

servlet如何从表单中获取，并连续多次跳转如何，再次获取表单参数
 第一种方法：
（第一个Serverlet类   注意：本章未进行乱码处理，不能传汉字）

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {


            String name=request.getParameter("name");
            String password=request.getParameter("password");

            if(name.equals("456") && password.equals("123")){
                 ServletContext context=this.getServletContext();
           context.setAttribute("name", name);            
           response.sendRedirect("successful");
            }
}

（第二个Serverlet类---》也就是第一个Serverlet类挑转到successful.java ）

public void doPost(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {             ServletContext context=this.getServletContext();System.out.println(context.getAttribute("name"));}

第二种（较为简单，使用forward（）注意：本章未进行乱码处理，不能传汉字）
类1

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {


            String name=request.getParameter("name");
            String password=request.getParameter("password");
              request.getRequestDispatcher("successful").forward(request, response);
}类2

public void doPost(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException { System.out.println("传参成功！！！");System.out.println(request.getParameter("name"));}