【初学者求助】我做了一个最简单的Servlet，可是部署上去之后，就是找不到，请高手帮忙

我做了一个Servlet，里面接受Web的POST请求，然后把所有的参数存入Oracle数据库中间的一个表。
可是，部署上去之后，一点Submit按钮，就说找不到Servlet。
请大家帮我看看好吗？
我的Web Container是jakarta-tomcat-5.0.19
Oracle 9i
报的错误是：
HTTP Status 404 - /tech-support/servlet/TechSupportServlet

--------------------------------------------------------------------------------

type Status report

message /tech-support/servlet/TechSupportServlet

description The requested resource (/tech-support/servlet/TechSupportServlet) is not available.

--------------------------------------------------------------------------------

Apache Tomcat/5.0.19

25 个解决方案

#1

楼主，请详细说明一下，你的类文件是如何放的，应该放到 web-inf/classes的文件下

#2

楼上讲的是一点
另外地址栏中url注意，尤其是端口。。

#3

下面是我的目录结构：
%tomcat_home%\webapps\tech-support\index.html
%tomcat_home%\webapps\tech-support\WEB-INF\web.xml
%tomcat_home%\webapps\tech-support\WEB-INF\classes\DbConnection.class
%tomcat_home%\webapps\tech-support\WEB-INF\classes\Sequencer.class
%tomcat_home%\webapps\tech-support\WEB-INF\classes\TechSupportServlet.class

下面是web.xml的内容：
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>TechSupportServlet Learning</servlet-name>
   <servlet-class>TechSupportServlet</servlet-class>
   </servlet>
</web-app>
请高手帮我看看，谢谢了。

#4

真的是郁闷，这么简单都搞不定

#5

我认为还是web.xml的问题
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>TechSupportServlet Learning</servlet-name>
   <servlet-class>TechSupportServlet</servlet-class>
   </servlet>
</web-app>
<servlet-mapping>
    <servlet-name>TechSupportServlet</servlet-name>
    <url-pattern>/TechSupportServlet</url-pattern> //请注意这里是否设置正确了，
                                                  //另外注意Jsp页面中调                                              //这个servlet时大小写是否一致
  </servlet-mapping>

#6

调用servlet的时候，action="/techSupportServlet"
action后面的是<url-pattern>/TechSupportServlet</url-pattern>中的部分，T小写

#7

web.xml内容改成如下试试

<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>tech</servlet-name>
   <servlet-class>TechSupportServlet</servlet-class>
   </servlet>
    <servlet-mapping>
        <servlet-name>tech</servlet-name>
        <url-pattern>/tech</url-pattern>//这是在浏览时的url
    </servlet-mapping>

</web-app>

然后在提交时提交到http://localhost:8080/tech

#8

各位老大的方法我都一一试过了，奇迹没有出现，还是老样子。
CoolAbu，我在HTML页面中是这样写的：
<FORM ACTION="/tech" METHOD="POST">
可是还是报错：
HTTP Status 404 - /tech

--------------------------------------------------------------------------------

type Status report

message /tech

description The requested resource (/tech) is not available.

--------------------------------------------------------------------------------

Apache Tomcat/5.0.19

#9

下面是我的HTML页面代码：
<HTML>
<HEAD>
  <TITLE>XYZ Corporation, IT Department</title>
</HEAD>
  <BODY>
    <H1>Technical Support Request</H1>
    <HR><BR>
    <CENTER>
      <FORM ACTION="/tech" METHOD="POST">
      <TABLE ALIGN="center" WIDTH="100%" CELLSPACING="2" CELLPADDING="2">
        <TR>
          <TD ALIGN="right">First Name:</TD>
          <TD><INPUT TYPE="Text" NAME="firstName" ALIGN="LEFT" SIZE="15"></TD>
          <TD ALIGN="right">Last Name:</TD>
          <TD><INPUT TYPE="Text" NAME="lastName" ALIGN="LEFT" SIZE="15"></TD>
        </TR>
        <TR>
          <TD ALIGN="right">Email:</TD>
          <TD><INPUT TYPE="Text" NAME="email" ALIGN="LEFT" SIZE="25"></TD>
          <TD ALIGN="right">Phone:</TD>
          <TD><INPUT TYPE="Text" NAME="phone" ALIGN="LEFT" SIZE="15"></TD>
        </TR>
        <TR>
          <TD ALIGN="right">Software:</TD>
          <TD>
            <SELECT NAME="software" SIZE="1">
              <OPTION VALUE="Word">Microsoft Word</OPTION>
              <OPTION VALUE="Excel">Microsoft Excel</OPTION>
              <OPTION VALUE="Access">Microsoft Access</OPTION>
            </SELECT>
          </TD>
          <TD ALIGN="right">Operating System:</TD>
          <TD>
            <SELECT NAME="os" size="1">
              <OPTION VALUE="95">Windows 95</OPTION>
              <OPTION VALUE="98">Windows 98</OPTION>
              <OPTION VALUE="NT">Windows NT</OPTION>
            </SELECT>
          </TD>
        </TR>
      </TABLE>

      <BR>Problem Description
      <BR>
      <TEXTAREA NAME="problem" COLS="50" ROWS="4"></TEXTAREA>

      <HR><BR>

      <INPUT TYPE="Submit" NAME="submit" VALUE="Submit Request">
    </FORM>
  </CENTER>
</BODY>
</HTML>

#10

下面是修改之后的web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>tech</servlet-name>
   <servlet-class>TechSupportServlet</servlet-class>
   </servlet>
    <servlet-mapping>
        <servlet-name>tech</servlet-name>
        <url-pattern>/tech</url-pattern>
    </servlet-mapping>
</web-app>

#11

你把Tomcat重启一次，然后用下面这个试试http://locahost:8080/tech-support/tech

Servlet基本上就是这样部署的，多试几次，以后就明白了。

#12

我已经重启了好几次了
没有用

不过非常感谢你，这么热心

#13

你的TechSupportServlet.java是怎么写的，如果有package name的话你应该这样部署：
例如你的TechSupportServlet.java 里有这样一句
package TechSupportServlet;
。。。。。
那么你的部署应该是这样的：
目录结构：

%tomcat_home%\webapps\tech-support\WEB-INF\classes\TechSupportServlet\TechSupportServlet.class

web.xml:

<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>tech</servlet-name>
   <servlet-class>TechSupportServlet.TechSupportServlet</servlet-class>
   </servlet>
    <servlet-mapping>
        <servlet-name>tech</servlet-name>
        <url-pattern>/tech</url-pattern>
    </servlet-mapping>
</web-app>

best regards!

#14

另外你在看看你的doPost()方法是否已经实现.

#15

1. don't deploy servlet without package

2. action="action" avoid using "/"

3. carefully study the examples on tomcat5.0

#16

楼主你把
<?xml version="1.0" encoding="ISO-8859-1"?>
换成

<?xml version="1.0" encoding="UTF-8"?>

这样试用一下
其它得不用改

#17

下面是TechSupportServlet.java的主要代码：
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import oracle.jdbc.driver.*;
import java.sql.*;
import javax.sql.*;

/**
* <p>Title: </p>
* <p>Description: </p>
* <p>Copyright: Copyright (c) 2004</p>
* <p>Company: </p>
* @author unascribed
* @version 1.0
*/

public class TechSupportServlet extends HttpServlet {
  static final private String CONTENT_TYPE = "text/html; charset=GBK";
  //数据库连接参数
  String protocol;
  String user;
  String password;
  //初始化数据库连接协议
  public void init() throws ServletException {
    String driver = getServletConfig().getInitParameter("driver");
    protocol = getServletConfig().getInitParameter("protocol");
    user = getServletConfig().getInitParameter("user");
    password = getServletConfig().getInitParameter("password");

    if (driver == null || protocol == null) {
      throw new UnavailableException("Driver not specified.");
    }

    try {
      Class.forName(driver);
    } catch (ClassNotFoundException cnfe) {
      throw new UnavailableException("Driver <" + driver
     + "> not found in the classpath.");
    }
  }
  //Process the HTTP Post request
  public void doPost(HttpServletRequest req,HttpServletResponse response) throws ServletException, IOException {
    //读取用户输入/选择
    String firstName = req.getParameter("firstName");
    String lastName = req.getParameter("lastName");
    String email = req.getParameter("email");
    String phone = req.getParameter("phone");
    String software = req.getParameter("software");
    String os = req.getParameter("os");
    String problem = req.getParameter("problem");

    //更新数据库
    int requestId = 0;
    Connection connection = null;
    String insertStatementStr =
"INSERT INTO SUPP_REQUESTS VALUES(?, ?, ?, ?, ?, ?, ?, ?)";
    try {
      //connection = DriverManager.getConnection(protocol);
      connection = DbConnection.getConnection(protocol,user,password);
      PreparedStatement insertStatement =
  connection.prepareStatement(insertStatementStr);
      requestId = Sequencer.getNextNumber(protocol,user,password);
      insertStatement.setInt(1, requestId);
      insertStatement.setString(2, firstName);
      insertStatement.setString(3, lastName);
      insertStatement.setString(4, email);
      insertStatement.setString(5, phone);
      insertStatement.setString(6, software);
      insertStatement.setString(7, os);
      insertStatement.setString(8, problem);
      insertStatement.executeUpdate();
    } catch (SQLException sqle) {
      throw new ServletException("Database error", sqle);
    }
    finally {
      if (connection != null) {
try {
  connection.close();
  }
catch (SQLException sqle) { }
      }
    }
    //产生应答页面
    response.setContentType(CONTENT_TYPE);
    PrintWriter out = response.getWriter();
    out.println("<HTML><HEAD><TITLE>");
    out.println("Tech Support: Request Confirmation");
    out.println("</TITLE></HEAD>");
    out.println("<BODY>");
    out.println("<H1>Tech Support: Request Confirmation</H1>");
    out.println("<P>Thank you for your request. Your request with the following reference number has been received.</P>");
    out.println("<P>Request Reference: " + requestId + "</P>");
    out.println("<P>Please note this number for future references.</P>");
    out.println("<P>Your request will be attended to within 24 hours.</P>");
    out.println("<P>Administrator <br>Techsupport team. </P>");
    out.println("</BODY></HTML>");
    out.close();
  }
  //Clean up resources
  public void destroy() {
  }
}

#18

to hiking:
我不同意你的第一点
因为我看了Tomcat5的servlet-examples
里面有一个HelloWorldExample.java
他就是不在任何包内

#19

to xinshou1979330：
您的方法，我也尝试了，不行。
下面是主要设置：
index.html:
<FORM ACTION="servlet/TechSupportServlet" METHOD="POST">

web.xml(我这是按照Tomcat里面自带实例做的配置):
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
   <servlet>
   <servlet-name>TechSupportServlet</servlet-name>
   <servlet-class>TechSupportServlet</servlet-class>
   </servlet>
    <servlet-mapping>
        <servlet-name>TechSupportServlet</servlet-name>
        <url-pattern>/servlet/TechSupportServlet</url-pattern>
    </servlet-mapping>
</web-app>

#20

回复人： EricHxy(龙真) ( ) 信誉：100

to hiking:
我不同意你的第一点
因为我看了Tomcat5的servlet-examples
里面有一个HelloWorldExample.java
他就是不在任何包内
===============================================================

没关系，这只是多次莫名其妙的失败中获得的。

理论上说，你可以把<url-pattern>/servlet/TechSupportServlet</url-pattern>中的/servlet/TechSupportServlet直接敲在IE中如：http://localhost:8080/yourwebapp/servlet/TechSupportServlet
有结果就对了，没有就有问题。

然后，还是要把servlet放在包中。

#21

to hiking:
我在IE中敲入：
http://localhost:8080/servlets-examples/servlet/HelloWorldExample
他的就是能够找到呢？
我看了代码，这个servlet也不在任何包里面啊？

#22

to hiking：
不管怎样，今天我就按照你的办法，加到包里面试试看

谢谢你

#23

搞不定，今天晚上散分

郁闷

#24

给大家推荐个好网站
http://www.djtz.net/get.asp?get=9662

#25

你的代码没有问题
首先确定你的serlet是不是放在web-inf/classes目录下
再看看你的web-inf是不是放在工作目录下,我的意思是必须放在工作目录下
比如你的工作目录是d:\jsp 那你就不能放到d:\jsp\serlet下,我用javabean时碰到过这中问题,再试试看,我不敢保证一定没有问题哦!

#1