java 字节流文件复制方法总结

时间：2022-07-01 21:02:12

1、使用字节流每次读写单个字节

 1 public static void main(String[] args) throws IOException {
 2         FileInputStream fis = new FileInputStream("C:\\CloudMusic\\1.mp3");
 3         FileOutputStream fos = new FileOutputStream("e:\\1.mp3");
 4         int len = 0;
 5         while ((len = fis.read()) != -1) {
 6             fos.write(len);
 7         }
 8         if (fos != null) {
 9             fos.close();
10         }
11         if (fis != null) {
12             fis.close();
13         }
14     }

2、使用字节流每次读写多个字节

 1 public static void main(String[] args) throws IOException {
 2         FileInputStream fis = new FileInputStream("C:\\CloudMusic\\1.mp3");
 3         FileOutputStream fos = new FileOutputStream("e:\\1.mp3");
 4         byte[] b = new byte[1024];
 5         int len = 0;
 6         while ((len = fis.read(b)) != -1) {
 7             fos.write(b,0,len);
 8         }
 9         if (fos != null) {
10             fos.close();
11         }
12         if (fis != null) {
13             fis.close();
14         }
15     }

3、使用字节缓冲流每次读写单个字节

 1 public static void main(String[] args) throws IOException {
 2         BufferedInputStream bis = new BufferedInputStream(new FileInputStream("C:\\CloudMusic\\1.mp3"));
 3         BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream("e:\\1.mp3"));
 4         int len = 0;
 5         while ((len = bis.read()) != -1) {
 6             bos.write(len);
 7         }
 8         if (bos != null) {
 9             bos.close();
10         }
11         if (bis != null) {
12             bis.close();
13         }
14     }

4、使用字节缓冲流每次读写多个字节

 1 public static void main(String[] args) throws IOException {
 2         BufferedInputStream bis = new BufferedInputStream(new FileInputStream("C:\\CloudMusic\\1.mp3"));
 3         BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream("e:\\1.mp3"));
 4         byte[] b = new byte[1024];
 5         int len = 0;
 6         while ((len = bis.read(b)) != -1) {
 7             bos.write(b, 0, len);
 8         }
 9         if (bos != null) {
10             bos.close();
11         }
12         if (bis != null) {
13             bis.close();
14         }
15     }

 

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