I'm attempting to match the last character in a WORD.
我在尝试匹配一个单词的最后一个字符。
A WORD is a sequence of non-whitespace characters '[^\n\r\t\f ]', or an empty line matching ^$.
一个单词是一个非空字符序列”[^ t \ n \ r \ \ f]”,或一个空行匹配^ $。
The expression I made to do this is: "[^ \n\t\r\f]\(?:[ \$\n\t\r\f]\)"
表达我是:“[^ \ n \ t f \ r \]\(?:[\ $ f \ n \ t \ r \]\)”
The regex matches a non-whitespace character that follows a whitespace character or the end of the line.
regex匹配一个空格字符或行尾的非空白字符。
But I don't know how to stop it from excluding the following whitespace character from the result and why it doesn't seem to capture a character preceding the end of the line.
但是我不知道如何阻止它从结果中排除下面的空格字符，以及为什么它似乎没有捕获行尾之前的字符。
Using the string "Hi World!", I would expect: the "i" and "!" to be captured.
使用字符串“Hi World!”，我希望“我”和“!”能够被抓住。
Instead I get: "i ".
相反，我得到的是“我”。
What steps can I take to solve this problem?
我可以采取什么措施来解决这个问题?
1 个解决方案
#1
3
Note that a non-capturing group (?:...) in [^ \n\t\r\f](?:[ \$\n\t\r\f]) still matches (consumes) the whitespace char (thus, it becomes a part of the match) and it does not match at the end of the string as the $ symbol is not a string end anchor inside a character class, it is parsed as a literal $ symbol.
注意,无组(?…)[^ \ n \ t f \ r \](?[\$\ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
You may use
你可以用
\S(?!\S)
See the regex demo
看到regex演示
The \S matches a non-whitespace char that is not followed with a non-whitespace char (due to the (?!\S) negative lookahead).
\S与非空白字符匹配，而非空白字符(由于(?!\S)为负的lookahead)。
#1
3
Note that a non-capturing group (?:...) in [^ \n\t\r\f](?:[ \$\n\t\r\f]) still matches (consumes) the whitespace char (thus, it becomes a part of the match) and it does not match at the end of the string as the $ symbol is not a string end anchor inside a character class, it is parsed as a literal $ symbol.
注意,无组(?…)[^ \ n \ t f \ r \](?[\$\ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
You may use
你可以用
\S(?!\S)
See the regex demo
看到regex演示
The \S matches a non-whitespace char that is not followed with a non-whitespace char (due to the (?!\S) negative lookahead).
\S与非空白字符匹配，而非空白字符(由于(?!\S)为负的lookahead)。