Symfony Routing Regex：如何编写可选字符？

I just have a little trouble with the symfony regex pattern in a routing config.

我对路由配置中的symfony正则表达式模式有点麻烦。

I would like to match both /keyword and /keyword/ URLs. The / character is optional.
Here is my pattern :

我想匹配/ keyword和/ keyword / URL。 /字符是可选的。这是我的模式:

pattern:  /{keyword}/?

/keyword/ matches the pattern, while /keyword does not.

/ keyword /匹配模式,而/ keyword则不匹配。

How should I write the pattern ?

我该怎么写这个模式?

3 个解决方案

#1

If you add the trailing slash, it is optional — a user will be redirected from the path without the slash to the path with it. So, the /{keyword}/ pattern will work for both /{keyword} and /{keyword}/.

如果添加尾部斜杠,则它是可选的 - 用户将从没有斜杠的路径重定向到带有它的路径。因此,/ {keyword} / pattern适用于/ {keyword}和/ {keyword} /。

However, if you define it without the trailing slash — /{keyword} — it will work for /{keyword} only.

但是,如果您定义它而没有斜杠 - / {keyword} - 它仅适用于/ {keyword}。

#2

I don't think you can have a RegEx pattern in a route. The keyword can be required to have a specific RegEx pattern, but that's a different matter.

我认为您不能在路线中使用RegEx模式。关键字可能需要具有特定的RegEx模式,但这是另一回事。

If you're using YML, then I think the best thing to do is to have two different routes:

如果您正在使用YML,那么我认为最好的办法是拥有两条不同的路线:

route1:
    pattern: /{keyword}
    ...

route2:
    pattern: /{keyword}/
    ...

If you're using annotations, you can put them both at the top of the controller action:

如果您正在使用注释,则可以将它们放在控制器操作的顶部:

/**
* @Route("/{keyword}");
* @Route("/{keyword}/");
*/

#3

In the controller where your function is use the annotations :

在您的函数使用注释的控制器中:

/**
 * Function
 * 
 * 
 * @Route("your/route/{keyword}")
 * @Route("your/route/{keyword}/")
 */

And you'll be able to access to this function with both routes.

并且您将能够使用这两个路径访问此功能。

#1