问题
Given an input string, reverse the string word by word.
For example, Given s = "the sky is blue", return "blue is sky the".
面试时我应该至少问的问题
- What constitutes a word? A sequence of non-space characters constitutes a word.
- Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces.
- How about multiple spaces between two words? Reduce them to a single space in the reversed string.
我大概想了下,但是没有问出来,需要改进!
代码分析
class Solution {
public:
static void reverseWords(string &s)
{
int len = s.length();
string result;
for(int i= len - 1; i >= 0; )
{
int lastend = 0;
while(i >= 0 && s[i] == ' ') //需要先判断i >=0,否则s[i]会出错
{
i--;
}
if(i < 0) //这里需要break,因为可能一连串的空格,没有任何字母,这时就应该及时退出
break;
lastend = i;
while(i >= 0 && s[i] != ' ') //这里也一样,需要先保证i在合法范围,再访问s[i]
{
i--;
} if(i <= lastend) // i may be -1
{
if(!result.empty())
result.append(" "); // 至少有一个字符串时,需要添加空格
result.append(s.substr(i+1, lastend - i));
}
} s.assign(result);
}
};