This question already has an answer here:
这个问题在这里已有答案：
- How to count the occurrences of a list item? 19 answers
- 如何计算列表项的出现次数？ 19个答案
I have 5 set of lists and some of strings in those lists are repetitive
我有5组列表，这些列表中的一些字符串是重复的
now! I wanna know the number of repetition! for example the word "A" is in all of my lists by "B" is just in "3" or "C" is in 4 of them.
现在！我想知道重复的次数！例如，单词“A”在我的所有列表中，“B”只是在“3”或“C”在其中4。
How can I sort this problem, by using remove() I faced to wrong answer
我如何通过使用remove（）来解决这个问题，我遇到了错误的答案
Thank you in advance!
先谢谢你！
1 个解决方案
#1
-2
Take a look at Counter
看看Counter
from collections import Counter
a = ['a','a','b','b']
b = ['b','b','c','d']
c = a+b
cnt = Counter()
for x in c:
cnt[x] +=1
print(cnt)
Counter({'a': 2, 'b': 4, 'c': 1, 'd': 1})
The above will get you counts of each but it seems like you're more concerned at a list level.
以上内容将为您提供各自的计数，但似乎您更关注列表级别。
from collections import defaultdict
f = defaultdict(list)
a = ['a','a','b','b']
b = ['b','b','c','d']
c = ['e','f','g','h']
d = a + b + c
for i in d:
f[i] = 0
if i in b:
f[i] += 1
if i in c:
f[i] +=1
if i in a:
f[i] +=1
print (f)
defaultdict(list,
{'a': 1, 'b': 2, 'c': 1, 'd': 1, 'e': 1, 'f': 1, 'g': 1, 'h': 1})
#1
-2
Take a look at Counter
看看Counter
from collections import Counter
a = ['a','a','b','b']
b = ['b','b','c','d']
c = a+b
cnt = Counter()
for x in c:
cnt[x] +=1
print(cnt)
Counter({'a': 2, 'b': 4, 'c': 1, 'd': 1})
The above will get you counts of each but it seems like you're more concerned at a list level.
以上内容将为您提供各自的计数，但似乎您更关注列表级别。
from collections import defaultdict
f = defaultdict(list)
a = ['a','a','b','b']
b = ['b','b','c','d']
c = ['e','f','g','h']
d = a + b + c
for i in d:
f[i] = 0
if i in b:
f[i] += 1
if i in c:
f[i] +=1
if i in a:
f[i] +=1
print (f)
defaultdict(list,
{'a': 1, 'b': 2, 'c': 1, 'd': 1, 'e': 1, 'f': 1, 'g': 1, 'h': 1})