Codeforces Round #202 (Div. 1) A. Mafia 贪心

时间：2023-03-08 17:27:08

A. Mafia

Time Limit: 20 Sec  Memory Limit: 256 MB

题目连接

http://codeforces.com/contest/348/problem/A

Description

One day n friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other n - 1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the i-th person wants to play ai rounds. What is the minimum number of rounds of the "Mafia" game they need to play to let each person play at least as many rounds as they want?

Input

The first line contains integer n (3 ≤ n ≤ 105). The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the i-th number in the list is the number of rounds the i-th person wants to play.

Output

In a single line print a single integer — the minimum number of game rounds the friends need to let the i-th person play at least ai rounds.

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Sample Input

3
3 2 2

Sample Output

4

HINT

题意

有n个人，在玩一个游戏，游戏表示每局都必须有个管理员参加

告诉你，每个人想当多少局玩家，然后让你求，最少多少局游戏，才能满足题意！

题解：

贪心就好了，类似厨师煮饼那道题一样

max（max_num,sum/(n-1));

代码：

//qscqesze

#include <cstdio>

#include <cmath>

#include <cstring>

#include <ctime>

#include <iostream>

#include <algorithm>

#include <set>

#include <vector>

#include <sstream>

#include <queue>

#include <typeinfo>

#include <fstream>

#include <map>

#include <stack>

typedef long long ll;

using namespace std;

//freopen("D.in","r",stdin);

//freopen("D.out","w",stdout);

#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)

#define test freopen("test.txt","r",stdin)

#define maxn 200001

#define mod 1000000007

#define eps 1e-9

int Num;

char CH[];

//const int inf=0x7fffffff;   //нчоч╢С

const int inf=0x3f3f3f3f;

inline ll read()

{

    ll x=,f=;char ch=getchar();

    while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}

    while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}

    return x*f;

}

inline void P(int x)

{

    Num=;if(!x){putchar('');puts("");return;}

    while(x>)CH[++Num]=x%,x/=;

    while(Num)putchar(CH[Num--]+);

    puts("");

}

//**************************************************************************************

ll a[maxn];

ll sum=;

ll mx=;

int main()

{

    int n=read();

    for(int i=;i<=n;i++)

        a[i]=read(),sum+=a[i],mx=max(a[i],mx);

    n=n-;

    ll ans;

    ans=sum/n;

    if(sum%n!=)

        ans++;

    cout<<max(mx,ans)<<endl;

}

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