Javascript嵌套数组返回偶数

I am trying to write a function that prints only the even numbers from a nested array. Here is my attempt and it keeps returning "undefined".

我正在尝试编写一个函数,只打印嵌套数组中的偶数。这是我的尝试,它不断返回“未定义”。

function printEvents(){

 var nestedArr = [[1,2,3],[4,5,6],[7,8],[9,10,11,12]];

  for (var i = 0; i<nestedArr.length; i++) {
    for (var j = 0; j<nestedArr[i]; j++) {
      var evenNumbers = nestedArr[i][j]
    }
  }

  if (evenNumbers % 2 == 0) {
    console.log(evenNumbers)
  }

 }

 printEvents();

4 个解决方案

#1

You could use a recursive approach, if the item is an array. You need to move the test for evenness inside of the for loop.

如果项是数组,则可以使用递归方法。您需要在for循环内移动测试以获得均匀度。

function printEvents(array) {
    var i;
    for (i = 0; i < array.length; i++) {
        if (Array.isArray(array[i])) {
            printEvents(array[i]);
            continue;
        }
        if (array[i] % 2 == 0) {
            console.log(array[i]);
        }
    }
}

printEvents([[1, 2, 3], [4, 5, 6], [7, 8], [9, 10, 11, 12], [[[13, [14]]]]]);

Solution with a callback

带回调的解决方案

function getEven(a) {
    if (Array.isArray(a)) {
        a.forEach(getEven);
        return;
    }
    if (a % 2 == 0) {
        console.log(a);
    }
}

getEven([[1, 2, 3], [4, 5, 6], [7, 8], [9, 10, 11, 12], [[[13, [14]]]]]);

#2

You just have a couple issues. You need to check the length of your nested arrays and you need to move your code that checks whether a number is even or not inside the array.

你只有几个问题。您需要检查嵌套数组的长度,并且需要移动代码来检查数组中数字是否均匀。

 var nestedArr = [[1,2,3],[4,5,6],[7,8],[9,10,11,12]];

  for (var i = 0; i<nestedArr.length; i++) {
    for (var j = 0; j<nestedArr[i].length; j++) {
      var evenNumbers = nestedArr[i][j]
      if (evenNumbers % 2 == 0) {
        console.log(evenNumbers)
      }
    }
  }

#3

You can do this more easy using filter method which accepts a callback method.

使用接受回调方法的filter方法可以更轻松地完成此操作。

var nestedArr = [[1,2,3],[4,5,6],[7,8],[9,10,11,12]];
var mergedArray=[].concat.apply([], nestedArr);
console.log(mergedArray.filter(a=>a%2==0));

#4

You can use reduce with every for something quick.

您可以快速使用reduce with every。

var nestedArr = [ [1, 2, 3],[4, 5, 6],[7, 8],[9, 10, 11, 12]];

var sift = nestedArr.reduce(function(r,o) {
    o.every(i => i % 2 === 0 ? r.push(i) : true)
    return r;
}, []);

console.log(sift);

If you want a one-liner you can use ReduceRight with Filter

如果你想要一个单行,你可以使用ReduceRight和Filter

var nestedArr = [[1, 2, 3],[4, 5, 6],[7, 8],[9, 10, 11, 12]];

var sift = nestedArr.reduceRight((p, b) => p.concat(b).filter(x => x % 2 === 0), []);

console.log(sift)

#1