I have a question about keeping query result in array. For example I execute a query
我有一个关于将查询结果保存在数组中的问题。例如,我执行一个查询
SELECT * FROM some_table
SELECT * FROM some_table
Then I want to save it to array and create records. The table contains these columns:
然后我想将它保存到数组并创建记录。该表包含以下列:
- id
- ID
- user_name
- 用户名
- last_name
- 姓
The result array can be:
结果数组可以是:
[[1, "First user name", "First last name"],
[2, "Second user name", "Second last name"]
...
].
Can you recommend me which array or data type should I use?
你能推荐一下我应该使用哪种数组或数据类型吗?
2 个解决方案
#1
0
You do that like this:
你这样做:
- Create a bean class for User
- 为User创建一个bean类
public class User { private int id; private String firstName; private String lastName; // getter and setter ... }
And then query all the data from table, and create a User object and set the data.
然后查询表中的所有数据,并创建一个User对象并设置数据。
List<User> users = new ArrayList<>();
while(someValue) {
...
int id = ...
String firstName= ...
String lastName = ...
User user = new User();
user.setId(id);
user.setFirstName(firstName);
user.setLastName(lastName);
users .add(user);
}
// after do what you want with the list
#2
0
I extend your question to "the best way to keep select result" (with or without array).
我将您的问题扩展到“保持选择结果的最佳方式”(有或没有数组)。
It depends on:
这取决于:
-
how many results
有多少结果
-
how many fields
有多少个字段
-
what do you want to do after ?
你想做什么?
-
do you want to modify, put in your database again ?
你想修改,再次放入你的数据库?
So, several propositions:
所以,几个命题:
-
just arrays: String[] fields1; String[] fields2, ...
只是数组:String [] fields1; String [] fields2,...
-
array of arrays: String[][];
数组数组:String [] [];
-
better collections: Vector, List or Set: do you want them to be sorted ?, how do you pick them after ? Or Map, (if you want to keep index => data)
更好的集合:矢量,列表或集合:你想要它们被排序吗?,你如何选择它们?或Map,(如果你想保留index => data)
-
or Object you create yourself. For this, you even have tools to map object-database.
或您自己创建的对象。为此,您甚至可以使用工具来映射对象数据库。
you should take a look at these features, and what you want to do .
你应该看看这些功能,以及你想做什么。
Hope it helps.
希望能帮助到你。
#1
0
You do that like this:
你这样做:
- Create a bean class for User
- 为User创建一个bean类
public class User { private int id; private String firstName; private String lastName; // getter and setter ... }
And then query all the data from table, and create a User object and set the data.
然后查询表中的所有数据,并创建一个User对象并设置数据。
List<User> users = new ArrayList<>();
while(someValue) {
...
int id = ...
String firstName= ...
String lastName = ...
User user = new User();
user.setId(id);
user.setFirstName(firstName);
user.setLastName(lastName);
users .add(user);
}
// after do what you want with the list
#2
0
I extend your question to "the best way to keep select result" (with or without array).
我将您的问题扩展到“保持选择结果的最佳方式”(有或没有数组)。
It depends on:
这取决于:
-
how many results
有多少结果
-
how many fields
有多少个字段
-
what do you want to do after ?
你想做什么?
-
do you want to modify, put in your database again ?
你想修改,再次放入你的数据库?
So, several propositions:
所以,几个命题:
-
just arrays: String[] fields1; String[] fields2, ...
只是数组:String [] fields1; String [] fields2,...
-
array of arrays: String[][];
数组数组:String [] [];
-
better collections: Vector, List or Set: do you want them to be sorted ?, how do you pick them after ? Or Map, (if you want to keep index => data)
更好的集合:矢量,列表或集合:你想要它们被排序吗?,你如何选择它们?或Map,(如果你想保留index => data)
-
or Object you create yourself. For this, you even have tools to map object-database.
或您自己创建的对象。为此,您甚至可以使用工具来映射对象数据库。
you should take a look at these features, and what you want to do .
你应该看看这些功能,以及你想做什么。
Hope it helps.
希望能帮助到你。