mysql数据库的相关练习题及答案

时间:2024-11-16 08:37:07

表结构示意图:

mysql数据库的相关练习题及答案

表结构创建语句:

class表创建语句
create table class(cid int not null auto_increment primary key, caption varchar() not null)engine=innodb default charset=utf8; student表创建语句
create table student(
-> sid int not null auto_increment primary key,
-> sname varchar() not null,
-> gender varchar() not null,
-> class_id int not null)engine=innodb default charset=utf8; teacher表创建语句
create table teacher(
-> tid int not null auto_increment primary key,
-> tname varchar() not null)engine=innodb default charset=utf8; course表创建语句
create table course(
-> cid int not null auto_increment primary key,
-> cname varchar() not null,
-> teacher_id int not null)engine=innodb default charset=utf8; score表创建语句
create table score(
-> sid int not null auto_increment primary key,
-> student_id int not null,
-> corse_id int not null,
-> number int not null)engine=innodb default charset=utf8;

创建相关表

、自行创建测试数据
、查询“生物”课程比“物理”课程成绩高的所有学生的学号;
select A.student_id,sw,ty from (select student_id,number as sw from score left join course on score.corse_id = course.cid where course.cname = '生物') as A left join (select student_id,number as ty from score left join course on score.corse_id = course.cid where course.cname = '体育') as B on A.student_id = B.student_id where sw > if(isnull(ty),,ty); 、查询平均成绩大于60分的同学的学号和平均成绩; 思路:
产寻学生的id,和成绩,然后用avg函数来求得同一id号的学生平均成绩,并用having进行成绩的筛选
select student_id,avg(number) from score group by student_id having avg(number)>; 增加显示学生名
select student_id,student.sname,avg(number) from score left join student on score.student_id=student.sid group by student_id having avg(number)>; 第二种实现方式
个人觉得这种方式好理解一些,语法结构是
先通过select student_id,avg(number) as stu_num from score group by student_id语句分组将数据取出并起临时表别名为SCORE,然后在和student表进行连表。
select SCORE.student_id,SCORE.stu_num from (select student_id,avg(number) as stu_num from score group by student_id) as SCORE left join student on SCORE.student_id=student.sid; 、查询所有同学的学号、姓名、选课数、总成绩;
语句进化过程:
()先讲student表关联起来,关联条件是student_id
select * from score left join student on score.student_id = student.sid;
()再通过条件筛选自己需要显示的内容,用limit来分页显示
select score.student_id,student.sname,score.corse_id,score.number from score left join student on score.student_id = student.sid limit ;
()用聚合函数count来统计课程数,用sum来算成绩的合。
select score.student_id,student.sname,count(score.corse_id),sum(score.number) from score left join student on score.student_id = student.sid group by score.student_id limit ;
终极:
select score.student_id,student.sname,count(score.corse_id),sum(score.number) from score left join student on score.student_id = student.sid group by score.student_id; 、查询姓“李”的老师的个数;
select count(tname) from teacher where tname like "李%"; 、查询没学过“叶平”老师课的同学的学号、姓名;
()查出李平老师所受的课
select cid from course left join teacher on course.teacher_id=teacher.tid where teacher.tname="李平老师";
()查出选择李平老师讲课的学生
select * from score where score.corse_id in (select cid from course left join teacher on course.teacher_id=teacher.tid where teacher.tname="李平老师")
()排除选择李平老师讲课的学生
select sid,sname from student where student.sid not in (select student_id from score where score.corse_id in (select cid from course left join teacher on course.teacher_id=teacher.tid where teacher.tname="李平老师")); 、查询学过“”并且也学过编号“”课程的同学的学号、姓名;
()取出课程id是1和2的课程
select * from score where corse_id= or corse_id=;
()通过student_id来进行分组根据having来过来选择两门的学生
select NEW_C.student_id,count(NEW_C.corse_id) as NUM from (select student_id,corse_id from score where corse_id= or corse_id=) as NEW_C group by NEW_C.student_id having NUM=;
()连表
select A.id,student.sname from (select NEW_C.student_id as ID,count(NEW_C.corse_id) as NUM from (select student_id,corse_id from score where corse_id= or corse_id=) as NEW_C group by NEW_C.student_id having NUM=) as A left join student on A.ID=student.sid; 、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
()连表查询课程和老师,并过滤出李平老师
select cid,cname,teacher.tname from course left join teacher on course.teacher_id=teacher.tid where teacher.tname='李平老师';
()查出选择李平老师课程的学生id
select * from score where corse_id in (select cid from course left join teacher on course.teacher_id=teacher.tid where teacher.tname='李平老师') group by student_id;
()关联学生表显示姓名
select A.student_id,student.sname from (select score.student_id from score where score.corse_id in (select course.cid from course left join teacher on course.teacher_id=teacher.tid where teacher.tname='李平老师') group by student_id) as A left join student on A.student_id=student.sid; 、查询课程编号“”的成绩比课程编号“”课程低的所有同学的学号、姓名;
select A.student_id,num_id1,num_id2 from (select student_id,number as num_id1 from score where corse_id=) as A left join (select student_id,number as num_id2 from score where corse_id=) as B on A.student_id = B.student_id where num_id1 > if(isnull(num_id2),,num_id2); 、查询有课程成绩小于60分的同学的学号、姓名;
select student.sid,student.sname from (select score.student_id from score where score.number < group by score.student_id) as A left join student on student.sid= A.student_id; 、查询没有学全所有课的同学的学号、姓名;
select student.sid,student.sname from (select student_id,count(corse_id) as S_NUM from score group by student_id having S_NUM < (select count(cname) as C_NUM from course)) as A left join student on student.sid=A.student_id; 、查询至少有一门课与学号为“”的同学所学相同的同学的学号和姓名;
()查询学生所选课程是否在学生id为1的学生的课程里面
select student_id from score where student_id != and score.corse_id in(select corse_id from score where student_id = ) group by student_id;
()和学生表关联取出相关的ID和姓名
select student.sid,student.sname from (select student_id from score where student_id != and score.corse_id in(select corse_id from score where student_id = ) group by student_id) as A left join student on A.student_id=student.sid; 、查询至少学过学号为“”同学所选课程中任意一门课的其他同学学号和姓名;
select student.sid,student.sname from (select student_id from score where student_id != and score.corse_id in(select corse_id from score where student_id = ) group by student_id having count(corse_id)=(select count(corse_id) from score where student_id=)) as A left join student on A.student_id=student.sid; 、查询和“”号的同学学习的课程完全相同的其他同学学号和姓名;
()和002号同学选择的个数相同的学生id
select student_id,count(student_id) from score group by student_id having count(student_id) = (select count() as a from score where student_id=)
()在筛选和002好同学选择课程名相同的学生id
select student_id,sname from score left join student on score.student_id = student.sid where student_id in (select student_id from score group by student_id having count(student_id) = (select count() as a from score where student_id=)) and corse_id in (select corse_id from score where student_id =) group by student_id having count(corse_id) = (select count() as a from score where student_id=); 、删除学习“叶平”老师课的SC表记录;
delete from score where corse_id in (select cid from course left join teacher on course.teacher_id = teacher.tid where teacher.tname = "李平老师"); 、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号“”课程的同学学号;②插入“”号课程的平均成绩;?
select student_id,,(select avg(number) from score where corse_id =) as a from score where student_id not in (select student_id from score where corse_id=) group by student_id; insert into score (student_id,corse_id,number) select student_id,,(select avg(number) from score where corse_id =) as a from score where student_id not in (select student_id from score where corse_id=) group by student_id; 、按平均成绩从低到高显示所有学生的“语文”、“数学”、“英语”三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分; 第一种实现方式
select SC.student_id,(select number from score where score.student_id = SC.student_id and corse_id = ) as sw,(select number from score where score.student_id = SC.student_id and corse_id = ) as wl,(select number from score where score.student_id = SC.student_id and corse_id = ) as ty,(select number from score where score.student_id = SC.student_id and corse_id = ) as ms,count(SC.corse_id),avg(SC.number) from score as SC group by SC.student_id order by avg(SC.number) desc; 第二种实现方式
select SC.student_id,(select number from score left join course on score.corse_id = course.cid where course.cname = "生物" and score.student_id = SC.student_id) as sw,(select number from score left join course on score.corse_id = course.cid where course.cname = "物理" and score.student_id = SC.student_id) as wl,(select number from score left join course on score.corse_id = course.cid where course.cname = "体育" and score.student_id = SC.student_id) as ty,(select number from score left join course on score.corse_id = course.cid where course.cname = "美术" and score.student_id = SC.student_id) as ms,count(SC.corse_id),avg(SC.number) from score as SC group by SC.student_id order by avg(SC.number) desc; 、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;
思路:通过课程id来进行分组,这个时候会显示四行,然后用聚合函数max,min来找出最大值和最小值。
select corse_id,max(number) as max_num,min(number) as min_num from score group by corse_id; 、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
新知识点:case when then相当于if判断
select corse_id,avg(number),sum(case when score.number> then else end)/count()* as jgl from score group by corse_id; 、课程平均分从高到低显示(现实任课老师);
select A.avg_num,course.cname,teacher.tname from (select avg(number) as avg_num,corse_id from score group by corse_id) as A left join course on course.cid = A.corse_id left join teacher on teacher.tid = course.teacher_id order by A.avg_num desc; 、查询各科成绩前三名的记录:(不考虑成绩并列情况)?
select score.sid,score.corse_id,score.number,T.first_num,T.second_num from score left join (select sid,(select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit ,) as first_num, (select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit ,) as second_num from score as s1) as T on score.sid =T.sid where score.number <= T.first_num and score.number >= T.second_num; 、查询每门课程被选修的学生数;
select corse_id,count(score.student_id) from score group by score.corse_id; 、查询出只选修了一门课程的全部学生的学号和姓名;
select A.c_id,student.sname from (select count(corse_id) as c_id,student_id from score group by student_id) as A left join student on student.sid=A.student_id having A.c_id =; 、查询男生、女生的人数;
select * from (select count() as M from student where gender="男") as A,(select count() as W from student where gender="女") as B; 、查询姓“张”的学生名单;
select sname from student where sname like "张%"; 、查询同名同姓学生名单,并统计同名人数;
select count(sname) from student group by sname; 、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;
select corse_id,avg(number) from score group by corse_id order by avg(number) asc,corse_id desc; 、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;
select A.student_id,student.sname,A.avg_num from (select avg(number) as avg_num,student_id from score group by student_id having avg_num > ) as A left join student on student.sid = A.student_id; 、查询课程名称为“数学”,且分数低于60的学生姓名和分数;
select A.student_id,student.sname,A.number from (select student_id,number from score where corse_id=(select cid from course where cname="生物") having number < ) as A left join student on student.sid = A.student_id; 、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
第一种
select A.student_id,student.sname from (select student_id,number from score where corse_id= group by student_id having number > ) as A left join student on student.sid=A.student_id;
第二种
select * from score where score.student_id = and score.num > 、求选了课程的学生人数
select count(A.student_id) from (select student_id from score group by student_id) as A; 、查询选修“杨艳”老师所授课程的学生中,成绩最高的学生姓名及其成绩;
select score.corse_id,student.sname,score.number from score left join student on score.student_id=student.sid where score.corse_id in (select course.cid from course left join teacher on course.teacher_id=teacher.tid where tname = "刘海燕老师") order by score.number desc limit ; 、查询各个课程及相应的选修人数;
第一种
select A.c_num,course.cname from (select count(student_id) as c_num,corse_id from score where corse_id in (select cid from course) group by corse_id) as A left join course on course.cid =A.corse_id ;
第二种
select course.cname,count() from score left join course on score.corse_id = course.cid group by corse_id; 、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;
select DISTINCT s1.corse_id,s2.corse_id,s1.number,s2.number from score as s1, score as s2 where s1.number = s2.number and s1.corse_id != s2.corse_id; 、查询每门课程成绩最好的前两名;
select score.sid,score.corse_id,score.number,T.first_num,T.second_num from score left join (select sid,(select number from score as s2 where s2.corse_id=s1.corse_id order by number desc limit ,)as first_num, (select number from score as s2 where s2.corse_id=s1.corse_id order by number desc limit ,) as second_num from score as s1) as T on score.sid = T.sid where score.number <= T.first_num and score.number >= T.second_num; 、检索至少选修两门课程的学生学号;
select student_id,count(corse_id) from score group by student_id having count(corse_id)> 、查询全部学生都选修的课程的课程号和课程名;
select count(student_id) from score group by corse_id having count(student_id) = (select count(sid) from student); 、查询没学过“叶平”老师讲授的任一门课程的学生姓名;
第一种
select sname from(select A.student_id as n_s_id from (select student_id,corse_id from score) as A left join course on course.cid=A.corse_id where course.teacher_id not in (select tid from teacher where tname="李平老师") group by A.student_id ) as B left join student on student.sid=B.n_s_id; 第二种
select student_id,student.sname from score left join student on score.student_id = student.sid where score.corse_id not in (select cid from course left join teacher on course.teacher_id = teacher.tid where tname = "李平老师") group by student_id; 、查询两门以上不及格课程的同学的学号及其平均成绩;
select avg(number) from score where student_id in (select student_id from score where number < group by student_id having count(corse_id) >); 、检索“”课程分数小于60,按分数降序排列的同学学号;
select A.number,student.sname,student.sid from (select score.number,score.student_id from score where score.corse_id = and score.number<) as A left join student on student.sid = A.student_id order by A.number desc; 、删除“”同学的“”课程的成绩;
delete from score where corse_id = and student_id =

参考:

http://www.cnblogs.com/wupeiqi/articles/5729934.html

http://www.cnblogs.com/wupeiqi/articles/5748496.html