How to Pass value from text using @html.actionlink in asp.net mvc3 ?
如何在asp.net mvc3中使用@html.actionlink传递文本中的值?
4 个解决方案
#1
5
Rather than passing your value using @Html.actionlink, try jquery to pass your textbox value to the controller as:
不要使用@ Html.actionlink传递您的值,而是尝试使用jquery将您的文本框值传递给控制器:
$(function () {
$('form').submit(function () {
$.ajax({
url: this.action,
type: this.method,
data: { search: $('#textboxid').val()},
success: function (result) {
$('#mydiv').html(result);
}
});
return false;
});
});
This code will post your textbox value to the controller and returns the output result which will be loaded in the div "mydiv".
此代码将您的文本框值发布到控制器并返回将在div“mydiv”中加载的输出结果。
#2
11
None of the answers here really work. The accepted answer doesn't refresh the page as a normal action link would; the rest simply don't work at all or want you to abandon your question as stated and quit using ActionLink
.
这里的答案都没有真正奏效。接受的答案不会刷新页面,因为正常的操作链接会;其余的根本不起作用或者希望你放弃你所说的问题并使用ActionLink退出。
MVC3/4
MVC3 / 4
You can use the htmlAttributes
of the ActionLink
method to do what you want:
您可以使用ActionLink方法的htmlAttributes来执行您想要的操作:
Html.ActionLink("My Link Title", "MyAction", "MyController", null, new { onclick = "this.href += '&myRouteValueName=' + document.getElementById('myHtmlInputElementId').value;" })
MVC5
MVC5
The following error has been reported, but I have not verified it:
已报告以下错误,但我尚未验证:
A potentially dangerous Request.Path value was detected
检测到潜在危险的Request.Path值
#3
2
to pass data from the client to the server you could use a html form:
要将数据从客户端传递到服务器,您可以使用html表单:
@using (Html.BeginForm(actionName,controllerName)) {
<input type="text" name="myText"/>
<input type="submit" value="Check your value!">
}
be sure to catch your myText variable inside your controller's method
一定要在控制器的方法中捕获myText变量
#4
-3
you can use this code (YourValue = TextBox.Text)
你可以使用这段代码(YourValue = TextBox.Text)
Html.ActionLink("Test", new { controller = "YourController", action = "YourAction", new { id = YourValue }, null );
public class YourController : Controller
{
public ActionResult YourAction(int id)
{
return View("here your value", id);
}
}
#1
5
Rather than passing your value using @Html.actionlink, try jquery to pass your textbox value to the controller as:
不要使用@ Html.actionlink传递您的值,而是尝试使用jquery将您的文本框值传递给控制器:
$(function () {
$('form').submit(function () {
$.ajax({
url: this.action,
type: this.method,
data: { search: $('#textboxid').val()},
success: function (result) {
$('#mydiv').html(result);
}
});
return false;
});
});
This code will post your textbox value to the controller and returns the output result which will be loaded in the div "mydiv".
此代码将您的文本框值发布到控制器并返回将在div“mydiv”中加载的输出结果。
#2
11
None of the answers here really work. The accepted answer doesn't refresh the page as a normal action link would; the rest simply don't work at all or want you to abandon your question as stated and quit using ActionLink
.
这里的答案都没有真正奏效。接受的答案不会刷新页面,因为正常的操作链接会;其余的根本不起作用或者希望你放弃你所说的问题并使用ActionLink退出。
MVC3/4
MVC3 / 4
You can use the htmlAttributes
of the ActionLink
method to do what you want:
您可以使用ActionLink方法的htmlAttributes来执行您想要的操作:
Html.ActionLink("My Link Title", "MyAction", "MyController", null, new { onclick = "this.href += '&myRouteValueName=' + document.getElementById('myHtmlInputElementId').value;" })
MVC5
MVC5
The following error has been reported, but I have not verified it:
已报告以下错误,但我尚未验证:
A potentially dangerous Request.Path value was detected
检测到潜在危险的Request.Path值
#3
2
to pass data from the client to the server you could use a html form:
要将数据从客户端传递到服务器,您可以使用html表单:
@using (Html.BeginForm(actionName,controllerName)) {
<input type="text" name="myText"/>
<input type="submit" value="Check your value!">
}
be sure to catch your myText variable inside your controller's method
一定要在控制器的方法中捕获myText变量
#4
-3
you can use this code (YourValue = TextBox.Text)
你可以使用这段代码(YourValue = TextBox.Text)
Html.ActionLink("Test", new { controller = "YourController", action = "YourAction", new { id = YourValue }, null );
public class YourController : Controller
{
public ActionResult YourAction(int id)
{
return View("here your value", id);
}
}