jQuery验证submitHandler在$中不起作用。ajax post表单数据

I am using the jquery validate plugin to send data from form to mysql database. the validation works well but after the button is clicked, the data isnt submitted to the database. but no response or error is generated. i think the error is in ajax part.

我正在使用jquery validate插件将数据从表单发送到mysql数据库。验证工作良好，但单击按钮后，数据没有提交到数据库。但是不会产生响应或错误。我认为错误在ajax部分。

The below file is db_connect.php, it executes .both echo are working

下面的文件是db_connect。这两个echo都在工作

<?php

echo "hello";
/* Database connection start */
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "upscfpyl_test";
$conn = mysqli_connect($servername, $username, $password, $dbname) or die("Connection failed: " . mysqli_connect_error());
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
echo "hi";
//exit();
}
else{
    echo "hi2";
}
?>

index.html - some code given below the div error is displayed but the content in it is hi2. I dont know why it has the content hi2. I had used echo "hi2"; in db_connect.php [code given at the end] but did not return it to ajax.

索引。在div错误下面显示了一些代码，但是其中的内容是hi2。我不知道为什么它有hi2的内容。我用了echo "hi2"在db_connect。php[最后给出的代码]，但没有返回给ajax。

<div id="error"></div>
<form id="signupForm" method="post" action="#">
<input type="submit" class="btn btn-primary" value="Sign Up" id="button1" name="btn-save">
</form>

Ajax part :

Ajax的部分:

$.ajax({
    type: 'POST',
    dataType: 'text',
    url: 'js/php/register.php',
    data: {
        name1: name,
        email1: email,
        mobile1: mobile,
        gender1: gender,
        password1: passwords
    },
    beforeSend: function() {
        $("#error").fadeOut();
        document.getElementById("button1").disabled = true; // this works
    },
    success : function(response) {
        if(response==1)
        {
            $("#error").fadeIn(1000, function()
            {
                $("#error").html('<div class="alert alert-danger"> <span class="glyphicon glyphicon-info-sign"></span>   Sorry email already taken !</div>');
                document.getElementById("button1").disabled = false;
            });
        } 
        else if(response=="registered")
        {
            window.location = "dashboard.html";
        } 
        else {
            $("#error").fadeIn(1000, function()
            {
                $("#error").html('<div class="alert alert-danger"><span class="glyphicon glyphicon-info-sign"></span>   '+response+' !</div>');
                document.getElementById("button1").disabled = false;
            });
        }
    }
});

登记。php -提交到数据库

<?php
include_once("db_connect.php");


function test_input($data) {
  $data = trim($data);
  $data = stripslashes($data);
  $data = htmlspecialchars($data);
  return $data;
}


if ($_SERVER["REQUEST_METHOD"] == "POST") {
  $name=test_input($_POST['name1']); // Fetching Values from URL.
  $email=test_input($_POST['email1']);
  $gender=test_input($_POST['gender1']);
  $mobile=test_input($_POST['mobile1']);
  $password= test_input(sha1($_POST['password1'])); // Password Encryption, If you like you can also leave sha1.

echo "pranav";    // these dont work
echo $name+$email+$gender; // this also doesnt work


  // Check if e-mail address syntax is valid or not
  $email = filter_var($email, FILTER_SANITIZE_EMAIL); // Sanitizing email(Remove unexpected symbol like <,>,?,#,!, etc.)
  if (!filter_var($email, FILTER_VALIDATE_EMAIL)){
    echo $email;
  } 
  else{
    $result = mysql_query("SELECT * FROM users WHERE email='$email'");
    $data = mysql_num_rows($result);
    if(($data)==0){
      $query = mysql_query("insert into users(name, email, password, gender, mobile) values ('$name', '$email', '$password', '$gender', '$mobile')"); // Insert query
      if($query){
        echo "registered";
      }
      else
      {
        echo "Error....!!";
      }
    }
    else
    {
      echo "1";
    }
  }
}
?>

1 个解决方案

#1

You can open your browser console for checking logs.

您可以打开浏览器控制台检查日志。

if the dataType is JSON, it means that your server is returning a json. But this is not the case see https://api.jquery.com/jQuery.ajax/

如果数据类型是JSON，则意味着服务器返回的是JSON。但事实并非如此，请参见https://api.jquery.com/jQuery.ajax/

Try this code for your data serialization:

为您的数据序列化尝试以下代码:

$("#your_form_id").submit(function(e){ 
    e.preventDefault(); 
    var datas = $(this).serialize(); 
    $.ajax({

        data: datas,
        // Or this
        data: 'key1=' + value1 + '&key2=' + value2 + '&key3=' + value3,

        // to match your server response
        dataType: "text"

        // Error warning
        .fail(function() {
           alert( "error" );
        })

    });
});

With the validation code of the form, we could better help you

有了表单的验证码，我们可以更好的帮助您

#1