I want to create a jQuery datepicker where sunday will be disabled and the previous days will be disabled including the present day after 3.30PM, and holidays also. Here is what I have done as far. can anyone help me how I can add the holidays?
我想创建一个jQuery日期选择器,其中星期日将被禁用,前几天将被禁用,包括当天下午3点30分以及假期。这是我到目前为止所做的。任何人都可以帮助我如何添加假期?
<!DOCTYPE html>
<html>
<head>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script>
var currentTime = new Date();
if (currentTime.getHours() >=15 && currentTime.getMinutes() >=30) {
$(document).ready(function() {
$('#datepicker').datepicker({
minDate: 1,
beforeShowDay: noSunday
});
function noSunday(date){
var day = date.getDay();
return [(day > 0), ''];
};
});
} else {
$(document).ready(function() {
$('#datepicker').datepicker({
minDate: 0,
beforeShowDay: noSunday
});
function noSunday(date){
var day = date.getDay();
return [(day > 0), ''];
};
});
}
</script>
</head>
<body>
<form>
<input id="datepicker" />
</form>
</body>
</html>
The Sunday disable and the before days are disabled I just need help to disable holiday
周日禁用和前几天被禁用我只需要帮助来禁用假期
1 个解决方案
#1
0
var currentTime = new Date();
var timeCond = currentTime.getHours() >=15 && currentTime.getMinutes() >=30;
var holidays = ["1/12/2016"]; // add holidays
$(document).ready(function() {
$('#datepicker').datepicker({
minDate: timeCond?1:0,
beforeShowDay: visibilityHandler
});
function visibilityHandler(date){
if(holidays.indexOf(date.toLocaleDateString()) != -1)
return [false,'']
return noSunday(date);
}
function noSunday(date){
var day = date.getDay();
return [(day > 0), ''];
};
});
#1
0
var currentTime = new Date();
var timeCond = currentTime.getHours() >=15 && currentTime.getMinutes() >=30;
var holidays = ["1/12/2016"]; // add holidays
$(document).ready(function() {
$('#datepicker').datepicker({
minDate: timeCond?1:0,
beforeShowDay: visibilityHandler
});
function visibilityHandler(date){
if(holidays.indexOf(date.toLocaleDateString()) != -1)
return [false,'']
return noSunday(date);
}
function noSunday(date){
var day = date.getDay();
return [(day > 0), ''];
};
});