元帅字符串^字符串。在marshal.h中获得一个错误

时间:2022-11-25 19:34:54

I have both of these in my class

我的课上有这两个

#include <msclr/marshal.h>
#include <msclr/marshal_cppstd.h>

and I have

和我有

using namespace msclr::interop;

I am using it to marshal String^ to string. Here is one example.

我用它来元帅字符串^字符串。这是一个例子。

string ProgReleaseType = marshal_as<std::string>(CurrentSubKey->GetValue("ReleaseType", NULL)->ToString());

When I build, I get this error.

当我构建时,我得到这个错误。

Error   53  error C4996: msclr::interop::error_reporting_helper<_To_Type,_From_Type,false>::marshal_as': This conversion is not supported by the library or the header file needed for this conversion is not included.  Please refer to the documentation on 'How to: Extend the Marshaling Library' for adding your own marshaling method.    C:\Program Files (x86)\Microsoft Visual Studio 12.0\VC\include\msclr\marshal.h  237

When I go into the marshal.h and read through line 237 is says to please use a marshal_context. I thought I was. I don't get what it doesn't like.

当我进入元帅。读第237行是为了使用marshal_context。我认为我是。我不知道它不喜欢什么。

3 个解决方案

#1


1  

Use a marshal context:

使用一个元帅上下文:

 msclr::interop::marshal_context context;

string ProgReleaseType = context.marshal_as<std::string>(CurrentSubKey->GetValue("ReleaseType", NULL)->ToString());

#2


2  

I'm unable to reproduce this error as described. That is the error I get if I include msclr\marshal.h but not msclr\marshal_cppstd.h. Double-check you're including it, or perhaps include it explicitly as the very first line in your cpp file.

我无法再现所描述的这个错误。如果我包含msclr\marshal,就会得到这个错误。h但不是msclr \ marshal_cppstd.h。再次检查您是否包含它,或者可能将它显式地包含为cpp文件中的第一行。

Here's my test application:

这是我的测试应用程序:

#include <msclr\marshal.h>
#include <msclr\marshal_cppstd.h>

using namespace msclr::interop;
using namespace System;
using namespace System::Diagnostics;

int main(array<System::String ^> ^args)
{
    String^ str = "Something";

    std::string stdstr = marshal_as<std::string>(str);

    stdstr[4] = '-';

    // Convert back to managed for printing.
    Debug::WriteLine(marshal_as<String^>(stdstr));

    return 0;
}

Output:

输出:

Some-hing

Some-hing

#3


1  

I hope this answer will help you.

我希望这个答案能对你有所帮助。

  1. Add header

    添加标题

     #include <msclr\marshal_cppstd.h>
    
  2. Here is sample code for String^ to string (standard string)

    这里的示例代码字符串^字符串(字符串)标准

      String^ str ="Sample string";
      msclr::interop::marshal_as<std::string>(str)
    

#1


1  

Use a marshal context:

使用一个元帅上下文:

 msclr::interop::marshal_context context;

string ProgReleaseType = context.marshal_as<std::string>(CurrentSubKey->GetValue("ReleaseType", NULL)->ToString());

#2


2  

I'm unable to reproduce this error as described. That is the error I get if I include msclr\marshal.h but not msclr\marshal_cppstd.h. Double-check you're including it, or perhaps include it explicitly as the very first line in your cpp file.

我无法再现所描述的这个错误。如果我包含msclr\marshal,就会得到这个错误。h但不是msclr \ marshal_cppstd.h。再次检查您是否包含它,或者可能将它显式地包含为cpp文件中的第一行。

Here's my test application:

这是我的测试应用程序:

#include <msclr\marshal.h>
#include <msclr\marshal_cppstd.h>

using namespace msclr::interop;
using namespace System;
using namespace System::Diagnostics;

int main(array<System::String ^> ^args)
{
    String^ str = "Something";

    std::string stdstr = marshal_as<std::string>(str);

    stdstr[4] = '-';

    // Convert back to managed for printing.
    Debug::WriteLine(marshal_as<String^>(stdstr));

    return 0;
}

Output:

输出:

Some-hing

Some-hing

#3


1  

I hope this answer will help you.

我希望这个答案能对你有所帮助。

  1. Add header

    添加标题

     #include <msclr\marshal_cppstd.h>
    
  2. Here is sample code for String^ to string (standard string)

    这里的示例代码字符串^字符串(字符串)标准

      String^ str ="Sample string";
      msclr::interop::marshal_as<std::string>(str)