如何使用JAXB对带有XML根元素的java列表进行编组?

I have huge list of java Objects, want to marshal that list without a root element, using JAXB. Is it possible to do ?.

我有大量的java对象列表，希望使用JAXB在没有根元素的情况下编组该列表。有可能吗?

I have a list something like this

我有一个这样的列表

List<Element> elements = new ArrayList<Element>

Expected Output:
<element>
  ----------
  ---------
</element>
<element>
  ---------
  ---------
<element>

How can I marshal in such a way,

我怎么能这样集结，

Any reference or hint will be greatly appreciated.

如有任何参考或提示，将不胜感激。

1 个解决方案

#1

You could iterate over the list marshalling each item individually. You will need to set the JAXB_FRAGMENT property on the Marshaller to prevent the XML header from being written out. You will only need to create the JAXBContext and Marshaller once for this use case.

您可以对列表进行迭代，分别对每个项进行编组。您需要在编组器上设置JAXB_FRAGMENT属性，以防止写入XML头。您只需要为这个用例创建JAXBContext和Marshaller。

import java.io.FileOutputStream;
import java.util.*;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Element.class);
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);

        List<Element> elements = new ArrayList<>();
        elements.add(new Element());
        elements.add(new Element());

        try(FileOutputStream fos = new FileOutputStream("src/forum18509018/out.txt")) {
           for(Element element : elements) {
               marshaller.marshal(element, fos);
           }
        }
    }

}