循环以使用文本对象填充框

时间:2022-04-13 09:13:13

I'm trying to make a game of "pick the color not the word" in Python. There is a list of 9 different colors:

我正试图在Python中制作一个“选择颜色而不是单词”的游戏。有9种不同颜色的列表:

cnames = [" green ", " blue ", " yellow ", " gray ", " pink ", " orange ", " purple ", " red ", " brown "]

I have written a function wich randomizes these colors:

我写了一个随机化这些颜色的函数:

def randomize():
    import random
    cnames=["green", "blue","yellow", "grey", "pink", "orange", "Purple", "red", "brown"]
    color=randint(0, len (cnames)-1)
    cname=randint(0, len(cnames)-1)

    from random import sample
    other_cnames=random.sample(range(len(cnames)),6)

    return (color, cname, other_cnames)

The code for the game window is:

游戏窗口的代码是:

win=GraphWin("New_game", 800,800)
    color, cname, other_names=randomize()

    rcname=cnames[cname]
    rcname=rcname [0].upper() + rcname[1:]
    target=Text(Point(300,100),rcname)
    target.setOutline(cnames[color])
    target.setStyle ("bold")
    target.setSize(24)
    target.draw(win)

    Boxes=[]
    k=0

How do I make a loop that fills the list boxes with text objects, where each text object is representing a color and the number of the color (0 to 8)?

如何创建一个用文本对象填充列表框的循环,其中每个文本对象表示颜色和颜色的数量(0到8)?

the result should look like this: enter image description here

结果应如下所示:在此处输入图像描述

2 个解决方案

#1


0  

You could use a for statement to iterate code a number of times to fill boxes like:

您可以使用for语句多次迭代代码以填充以下框:

for x in range(*insert number of boxes*): *put other code here*

for x in range(* insert number of boxes *):*将其他代码放在这里*

This will fill it up if you just put the range in

如果您只是放入范围,这将填补它

#2


0  

Not exactly sure what you have asked for, assuming you want to return color and color list without the color selected.

假设您想要在没有选择颜色的情况下返回颜色和颜色列表,则不确定您要求的内容。

cnames = ['green', 'blue'...]

to pick one color from list use random.choice

从列表中选择一种颜色使用random.choice

color = random.choice(cnames)

to get other colors init new list and pop by index

获取其他颜色初始化新列表并按索引弹出

other_colors = list(cnames)
other_colors.pop(colors.index(color))

return selected color and others

返回选定的颜色和其他

return color, other_colors

in graphwin

color, other_colors = randomize()

ucolor = '{0}{1}'.format(color[0].upper(), color[1:])
target = Text(Point(300,100),ucolor)
target.setOutline(color)
...
Boxes = other_colors # 

#1


0  

You could use a for statement to iterate code a number of times to fill boxes like:

您可以使用for语句多次迭代代码以填充以下框:

for x in range(*insert number of boxes*): *put other code here*

for x in range(* insert number of boxes *):*将其他代码放在这里*

This will fill it up if you just put the range in

如果您只是放入范围,这将填补它

#2


0  

Not exactly sure what you have asked for, assuming you want to return color and color list without the color selected.

假设您想要在没有选择颜色的情况下返回颜色和颜色列表,则不确定您要求的内容。

cnames = ['green', 'blue'...]

to pick one color from list use random.choice

从列表中选择一种颜色使用random.choice

color = random.choice(cnames)

to get other colors init new list and pop by index

获取其他颜色初始化新列表并按索引弹出

other_colors = list(cnames)
other_colors.pop(colors.index(color))

return selected color and others

返回选定的颜色和其他

return color, other_colors

in graphwin

color, other_colors = randomize()

ucolor = '{0}{1}'.format(color[0].upper(), color[1:])
target = Text(Point(300,100),ucolor)
target.setOutline(color)
...
Boxes = other_colors # 

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