题目:有四个数字:1、2、3、4,能组成多少个互不相同且无重复数字的三位数?各是多少?
程序分析:可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去 掉不满足条件的排列。
程序源代码:
源码:
#!/usr/bin/python
# -*- coding: UTF-8 -*-
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if( i != k ) and (i != j) and (j != k):
print i,j,k 我的源码: num=5
#num=raw_input("input number to get three-digital number:")
list1=range(1,num)
counter=0
for i in list1:
for j in list1:
if(i!=j):
for k in list1:
if(i!=j and j!=k and i!=k):
print(i*100+j*10+k)
counter+=1
else:
continue
else:
continue print("total :"+str(counter)) 其他人的解法参考:
使用列表形式,并计算总结:
#!/usr/bin/python
# -*- coding: UTF-8 -*- # 原答案没有指出三位数的数量,添加无重复三位数的数量 d=[]
for a in range(1,5):
for b in range(1,5):
for c in range(1,5):
if (a!=b) and (a!=c) and (c!=b):
d.append([a,b,c])
print "总数量:", len(d)
print d-
盼盼
946184399@qq.com
将for循环和if语句综合成一句,直接打印出结果
#!/usr/bin/env python
# -*- coding: UTF-8 -*- list_num = [1,2,3,4] list = [i*100 + j*10 + k for i in list_num for j in list_num for k in list_num if (j != i and k != j and k != i)] print (list) -
习惯乌龙茶
realsongtao@163.com
参考方法(设置最大,最小值):
#!/usr/bin/python
# -*- coding: UTF-8 -*- line=[]
for i in range(123,433):
a=i%10
b=(i%100)//10
c=(i%1000)//100
if a!=b and b!=c and a!=c and 0<a<5 and 0<b<5 and 0<c<5 :
print (i)
line.append(i)
print('the total is :',len(line))