如何找到所有的Javascript对象方法和属性?

I've found that sometimes I'll have a var with a bunch of methods and properties that I can't seem to locate somehow, event with Object.keys and Object.getOwnPropertyNames on both the var and the prototype.

我发现，有时我有一个带有很多方法和属性的var，我似乎无法找到它们，带有对象的事件。键和对象。在var和原型上都有getOwnPropertyNames。

Here's an example: I'm playing with RethinkDB and I want to override the run function. However, I don't know where it lives -- what object prototype I need to change, etc. In fact, I can't find any way of finding it with the functions I specified above:

这里有一个例子:我在玩RethinkDB，我想重写run函数。但是，我不知道它住在哪里——我需要改变什么对象原型，等等。事实上，我找不到任何方法来找到它和我上面指定的函数:

> r.db('test').tableCreate('authors').run
[Function]
> r.db('test').tableCreate('authors')
{ [Function]
  args: 
   [ { [Function] args: [Object], optargs: {} },
     { [Function] data: 'authors' } ],
  optargs: {} }
> r.db('test').tableCreate('authors').prototype
{}
> r.db('test').tableCreate('authors').run
[Function]
> Object.keys(r.db('test').tableCreate('authors'))
[ 'args', 'optargs' ]
> typeof r.db('test').tableCreate('authors')
'function'
> Object.getOwnPropertyNames( r.db('test').tableCreate('authors') )
[ 'length',
  'name',
  'arguments',
  'caller',
  'prototype',
  'args',
  'optargs' ]
> Object.getOwnPropertyNames( r.db('test').tableCreate('authors').prototype )
[ 'constructor' ]

The run function never shows up... Any ideas?

运行函数永远不会出现……什么好主意吗?

EDIT:

编辑:

I did some snooping in the source code. this is the method I want to wrap.

我在源代码中做了一些窥探。这就是我想要的方法。

Then, you can following the inheritance chain from TermBase to Eq (RDBVal, RDBOp, Eq).

然后，可以跟踪从TermBase到Eq (RDBVal, RDBOp, Eq)的继承链。

r.eq().run returns a function -- the function I want to wrap.

run返回一个函数——我想要包装的函数。

@T.J. Crowder's answer: findProps('run', r.eq()) prints out a bunch of stuff including:

@T.J。Crowder的回答是:findProps('run'， r.eq())打印出一堆东西，包括:

I20150625-10:33:31.047(-7)? Props for run[[Proto]][[Proto]][[Proto]][[Proto]]
I20150625-10:33:31.047(-7)? 0: constructor
I20150625-10:33:31.047(-7)? 1: showRunWarning
I20150625-10:33:31.047(-7)? 2: run

So thats it!

所以这就是它!

1 个解决方案

#1

Object.keys gives you that object's enumerable property names. Many properties are not enumerable.

对象。键提供对象的可枚举属性名。许多属性是不可枚举的。

As ssube said, you don't have to know at what level a property is defined to override it. But if you want to know, you can in ES5 and later, via Object.getOwnPropertyNames, which includes non-enumerable properties of an object, and Object.getPrototypeOf, which lets you traverse up the object's prototype chain.

正如ssube所说，您不需要知道在什么级别定义一个属性来覆盖它。但是如果你想知道，你可以在ES5中或者以后，通过Object。getOwnPropertyNames，包括对象的非可枚举属性和对象。getPrototypeOf，它允许您遍历对象的原型链。

Example:

例子:

function findProps(objname, obj) {
  var p;
  
  snippet.log("Props for " + objname);
  Object.getOwnPropertyNames(obj).forEach(function(name, index) {
    snippet.log(index + ": " + name);
  });
  p = Object.getPrototypeOf(obj);
  if (p != null) {
    findProps(objname + "[[Proto]]", p);
  }
}

var a = {};
Object.defineProperty(a, "foo", {      // A non-enumerable property
  value: "bar"
});

var b = Object.create(a);              // b's prototype is a
b.answer= 42;                          // An enumerable property
Object.defineProperty(a, "question", { // A non-enumerable property
  value: "Life, the Universe, and Everything"
});


var c = Object.create(b);              // c's prototype is b
c.last = "property";

findProps("c", c);

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