Java中静态代码块,静态变量,静态方法,构造方法初始化顺序

时间:2021-11-10 19:34:15

一个典型的例子如下:

<span style="font-size:18px;">public class Test {
	public static int k = 0;
	public static Test t1 = new Test("t1");
	public static Test t2 = new Test("t2");
	public static int i = print("i");
	public static int n = 99;
	
	public int j = print("j");
	
	{
		print("构造块");
	}
	
	static{
		print("静态块");
	}
	
	public Test(String str){
		System.out.println((++k)+":"+str+"   i="+i+"   n="+n);
		++i;
		++n;
	}
	
	public static int print(String str){
		System.out.println((++k)+":"+str+"   i="+i+"   n="+n);
		++n;
		return ++i;
	}
	
	public static void main(String...strings){
		Test t = new Test("init");
	}
}</span>

程序执行结果如下:

<span style="font-size:18px;">1:j   i=0   n=0
2:构造块   i=1   n=1
3:t1   i=2   n=2
4:j   i=3   n=3
5:构造块   i=4   n=4
6:t2   i=5   n=5
7:i   i=6   n=6
8:静态块   i=7   n=99
9:j   i=8   n=100
10:构造块   i=9   n=101
11:init   i=10   n=102</span>