Java中静态代码块,静态变量,静态方法,构造方法初始化顺序

时间:2022-08-30 19:34:08

一个典型的例子如下:

<span style="font-size:18px;">public class Test {
public static int k = 0;
public static Test t1 = new Test("t1");
public static Test t2 = new Test("t2");
public static int i = print("i");
public static int n = 99;

public int j = print("j");

{
print("构造块");
}

static{
print("静态块");
}

public Test(String str){
System.out.println((++k)+":"+str+" i="+i+" n="+n);
++i;
++n;
}

public static int print(String str){
System.out.println((++k)+":"+str+" i="+i+" n="+n);
++n;
return ++i;
}

public static void main(String...strings){
Test t = new Test("init");
}
}</span>

程序执行结果如下:

<span style="font-size:18px;">1:j   i=0   n=0
2:构造块 i=1 n=1
3:t1 i=2 n=2
4:j i=3 n=3
5:构造块 i=4 n=4
6:t2 i=5 n=5
7:i i=6 n=6
8:静态块 i=7 n=99
9:j i=8 n=100
10:构造块 i=9 n=101
11:init i=10 n=102</span>