题目如下:
Every email consists of a local name and a domain name, separated by the @ sign.
For example, in
alice@leetcode.com
,alice
is the local name, andleetcode.com
is the domain name.Besides lowercase letters, these emails may contain
'.'
s or'+'
s.If you add periods (
'.'
) between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name. For example,"alice.z@leetcode.com"
and"alicez@leetcode.com"
forward to the same email address. (Note that this rule does not apply for domain names.)If you add a plus (
'+'
) in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered, for examplem.y+name@email.com
will be forwarded tomy@email.com
. (Again, this rule does not apply for domain names.)It is possible to use both of these rules at the same time.
Given a list of
emails
, we send one email to each address in the list. How many different addresses actually receive mails?Example 1:
Input: ["test.email+alex@leetcode.com","test.e.mail+bob.cathy@leetcode.com","testemail+david@lee.tcode.com"]
Output: 2
Explanation: "testemail@leetcode.com" and "testemail@lee.tcode.com" actually receive mailsNote:
1 <= emails[i].length <= 100
1 <= emails.length <= 100
- Each
emails[i]
contains exactly one'@'
character.
解题思路:82%的通过率足以证明这题有多简单。把local name的 '.'替换成'',并且截断第一个'+'后面的内容即可。
代码如下:
class Solution(object):
def numUniqueEmails(self, emails):
"""
:type emails: List[str]
:rtype: int
"""
dic = {}
for i in emails:
e = i.split('@')
e[0] = e[0].replace('.','')
if '+' in e[0]:
e[0] = e[0][:e[0].index('+')]
if e[0] + '@' + e[1] not in dic:
dic[e[0] + '@' + e[1]] = 1
#print dic
return len(dic)