I am using react-native to build a android app, and I want to know how can I solve this situation: In Java code, some updating must notify the javascript to refresh the view!
我使用react-native来构建一个Android应用程序,我想知道如何解决这种情况:在Java代码中,一些更新必须通知javascript刷新视图!
1 个解决方案
#1
0
Yes, this is possible. There is more info on this page:
是的,这是可能的。此页面上有更多信息:
You need to signal the event back in the JavaScript with an emitter.
您需要使用发射器在JavaScript中发回事件。
I've not actually done this in practice as yet but I will have to soon. Let me know how you get on.
我实际上还没有在实践中做到这一点,但我将很快。让我知道你是怎么办的。
To use their example, in your Java:
要在Java中使用他们的示例:
...
private void sendEvent(ReactContext reactContext,
String eventName,
@Nullable WritableMap params) {
reactContext
.getJSModule(DeviceEventManagerModule.RCTDeviceEventEmitter.class)
.emit(eventName, params);
}
...
WritableMap params = Arguments.createMap();
...
sendEvent(reactContext, "keyboardWillShow", params);
Then in your JS:
然后在你的JS中:
var { DeviceEventEmitter } = require('react-native');
...
var ScrollResponderMixin = {
mixins: [Subscribable.Mixin],
componentWillMount: function() {
...
this.addListenerOn(DeviceEventEmitter,
'keyboardWillShow',
this.scrollResponderKeyboardWillShow);
...
},
scrollResponderKeyboardWillShow:function(e: Event) {
this.keyboardWillOpenTo = e;
this.props.onKeyboardWillShow && this.props.onKeyboardWillShow(e);
},
or, you can directly listen for the event in your JS:
或者,您可以直接在JS中监听事件:
...
componentWillMount: function() {
DeviceEventEmitter.addListener('keyboardWillShow', function(e: Event) {
// handle event.
});
}
...
#1
0
Yes, this is possible. There is more info on this page:
是的,这是可能的。此页面上有更多信息:
You need to signal the event back in the JavaScript with an emitter.
您需要使用发射器在JavaScript中发回事件。
I've not actually done this in practice as yet but I will have to soon. Let me know how you get on.
我实际上还没有在实践中做到这一点,但我将很快。让我知道你是怎么办的。
To use their example, in your Java:
要在Java中使用他们的示例:
...
private void sendEvent(ReactContext reactContext,
String eventName,
@Nullable WritableMap params) {
reactContext
.getJSModule(DeviceEventManagerModule.RCTDeviceEventEmitter.class)
.emit(eventName, params);
}
...
WritableMap params = Arguments.createMap();
...
sendEvent(reactContext, "keyboardWillShow", params);
Then in your JS:
然后在你的JS中:
var { DeviceEventEmitter } = require('react-native');
...
var ScrollResponderMixin = {
mixins: [Subscribable.Mixin],
componentWillMount: function() {
...
this.addListenerOn(DeviceEventEmitter,
'keyboardWillShow',
this.scrollResponderKeyboardWillShow);
...
},
scrollResponderKeyboardWillShow:function(e: Event) {
this.keyboardWillOpenTo = e;
this.props.onKeyboardWillShow && this.props.onKeyboardWillShow(e);
},
or, you can directly listen for the event in your JS:
或者,您可以直接在JS中监听事件:
...
componentWillMount: function() {
DeviceEventEmitter.addListener('keyboardWillShow', function(e: Event) {
// handle event.
});
}
...