hdu 1114 Piggy-Bank 动态规划+完全背包

题意：给出空罐的质量w1和满罐的质量w2，给出n个硬币的价值和质量，求该质量下最小的价值。 完全背包，d[i]=min(d[i],d[i-w[j]]+v[j]),(i为质量，j为硬币编号)。

#include <iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#define INF 0x7ffffff
#define N 550
#define M 11000
using namespace std;

int w[N],v[N],d[M];

int main()
{
    int T,w1,w2,w0,n;
    cin>>T;
    while(T--)
    {
        cin>>w1>>w2;
        w0=w2-w1;
        cin>>n;
        for(int i=0;i<n;i++)    cin>>v[i]>>w[i];
        for(int i=1;i<=w0;i++)  d[i]=INF;
        d[0]=0;
        for(int i=1;i<=w0;i++)
            for(int j=0;j<n;j++)
               if(i-w[j]>=0)    d[i]=min(d[i],d[i-w[j]]+v[j]);
        if(d[w0]>=INF)  printf("This is impossible.\n");
        else    printf("The minimum amount of money in the piggy-bank is %d.\n",d[w0]);
    }
}