Android加密和解密错误 - javax.crypto.IllegalBlockSizeException:解密时最后一个块不完整

时间:2022-10-06 18:33:48

I have an issue with the decryption in the following code. I have a encrypted string being sent to setData(). I am trying to decrypt the encrypted string(data). The error I keep getting is

我在以下代码中遇到了解密问题。我有一个加密的字符串发送到setData()。我试图解密加密的字符串(数据)。我一直得到的错误是

javax.crypto.IllegalBlockSizeException: last block incomplete in decryption

javax.crypto.IllegalBlockSizeException:解密时最后一个块不完整

byte[] data;
String key = "tkg96827pco74510";

byte[] encryptedOut;
String decryptedOut;

Key aesKey;
Cipher cipher;

public void setData(String dataIn){
    this.data = dataIn.getBytes();
    try {
        aesKey = new SecretKeySpec(key.getBytes(), "AES");
        cipher = Cipher.getInstance("AES");

    }catch(Exception e){
        System.out.println("SET DATA ERROR - " + e);
    }
}
public void encrypt() {
    try{
        cipher.init(Cipher.ENCRYPT_MODE, aesKey);
        encryptedOut = cipher.doFinal(data);
    }catch(Exception e){
        System.out.println(e);
    }
}

public void decrypt(){
    try {
        cipher.init(Cipher.DECRYPT_MODE, aesKey);
        decryptedOut = new String(cipher.doFinal(data));

    }catch(Exception e){
        System.out.println("Decrypt Error: " + e);
    }
}

public byte[] getEncrypted() {
   return encryptedOut;
}

public String getDecrypted(){
    return decryptedOut;
}

2 个解决方案

#1


The problem is caused by this line :

问题是由这条线引起的:

decryptedOut = new String(cipher.doFinal(data));

Here you are passing original data to decrypt. But you should pass encryptedOut here.

在这里,您将传递原始数据进行解密。但是你应该在这里传递encryptedOut。

So the solution would be :

所以解决方案是:

decryptedOut = new String(cipher.doFinal(encryptedOut));

and yes, Please pass some encoding mechanism to convert String to byteArray and vice-versa like "UTF-8".

是的,请传递一些编码机制将String转换为byteArray,反之亦然,如“UTF-8”。

So the correct line would be :

所以正确的路线是:

decryptedOut = new String(cipher.doFinal(encryptedOut),"UTF-8");

Given you have done conversion to bytes like this :

鉴于您已完成转换为字节,如下所示:

this.data = dataIn.getBytes("UTF-8");

#2


The problem is here:

问题出在这里:

public String getDecrypted()

and here:

decryptedOut = new String(cipher.doFinal(data));

String is not a container for binary data. You need to encode the cipher text somehow before you put it into a String. For example, base64-encoding.

String不是二进制数据的容器。在将密文放入String之前,需要以某种方式对密文进行编码。例如,base64编码。

#1


The problem is caused by this line :

问题是由这条线引起的:

decryptedOut = new String(cipher.doFinal(data));

Here you are passing original data to decrypt. But you should pass encryptedOut here.

在这里,您将传递原始数据进行解密。但是你应该在这里传递encryptedOut。

So the solution would be :

所以解决方案是:

decryptedOut = new String(cipher.doFinal(encryptedOut));

and yes, Please pass some encoding mechanism to convert String to byteArray and vice-versa like "UTF-8".

是的,请传递一些编码机制将String转换为byteArray,反之亦然,如“UTF-8”。

So the correct line would be :

所以正确的路线是:

decryptedOut = new String(cipher.doFinal(encryptedOut),"UTF-8");

Given you have done conversion to bytes like this :

鉴于您已完成转换为字节,如下所示:

this.data = dataIn.getBytes("UTF-8");

#2


The problem is here:

问题出在这里:

public String getDecrypted()

and here:

decryptedOut = new String(cipher.doFinal(data));

String is not a container for binary data. You need to encode the cipher text somehow before you put it into a String. For example, base64-encoding.

String不是二进制数据的容器。在将密文放入String之前,需要以某种方式对密文进行编码。例如,base64编码。