I have a map like so:
我有一张这样的地图:
[One:[example:value1, example2:value2] ,Two[example 1:value3, example2:value4]]
I'm am matching value1 from a value in another map, but I need to get the keys,either One or Two depending on if it is a match.
我正在从另一个地图中的值匹配value1,但我需要获取一个或两个键,具体取决于它是否匹配。
So if I say:
所以,如果我说:
if( value1.equals (otherMapValue))
Return One
This map is from a json response so if there is a better way to do this besides a map I can change it. Sorry for the formatting I'm using my phone
这个地图来自json响应,所以除了地图之外还有更好的方法可以改变它。对不起格式化我正在使用手机
1 个解决方案
#1
1
This should do:
这应该做:
def someMethod(valueFromOthermap) {
def map = [
One: [example1: 'value1', example2:'value2'],
Two: [example1: 'value3', example2:'value4']
]
map.findResults { k, v ->
valueFromOthermap in v.values() ? k : null
}
}
assert someMethod('value1') == ['One']
If you are looking for the first matching key instead of a list of keys, then use findResult
instead of findResults
, everything else remains unchanged.
如果您正在寻找第一个匹配键而不是键列表,那么使用findResult而不是findResults,其他一切都保持不变。
UPDATE:
Regarding JSON to Map
parsing, a JSON resonse can be easily parsed to Map
as shown below:
更新:关于JSON to Map解析,可以很容易地将JSON共振解析为Map,如下所示:
Map responseMap = new groovy.json.JsonSlurper().parseText( jsonResponseString )
#1
1
This should do:
这应该做:
def someMethod(valueFromOthermap) {
def map = [
One: [example1: 'value1', example2:'value2'],
Two: [example1: 'value3', example2:'value4']
]
map.findResults { k, v ->
valueFromOthermap in v.values() ? k : null
}
}
assert someMethod('value1') == ['One']
If you are looking for the first matching key instead of a list of keys, then use findResult
instead of findResults
, everything else remains unchanged.
如果您正在寻找第一个匹配键而不是键列表,那么使用findResult而不是findResults,其他一切都保持不变。
UPDATE:
Regarding JSON to Map
parsing, a JSON resonse can be easily parsed to Map
as shown below:
更新:关于JSON to Map解析,可以很容易地将JSON共振解析为Map,如下所示:
Map responseMap = new groovy.json.JsonSlurper().parseText( jsonResponseString )