无法通过AJAX post发送'+' ?

I am using Ajax POST method to send data, but i am not able to send '+'(operator to the server i.e if i want to send 1+ or 20k+ it will only send 1 or 20k..just wipe out '+') HTML code goes here..

我正在使用Ajax POST方法发送数据，但是我不能发送'+'(操作员)到服务器I。如果我想发送1+或20k+，它只会发送1或20k。删除'+')HTML代码到这里。

<form method='post' onsubmit='return false;' action='#'>
  <input type='input' name='salary' id='salary' />
  <input type='submit' onclick='submitVal();' />
</form>

and javascript code goes here,

javascript代码在这里，

function submitVal()
{
     var sal=document.getElementById("salary").value;
     alert(sal);
     var request=getHttpRequest();
     request.open('post','updateSal.php',false);
     request.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
     request.send("sal="+sal);

     if(request.readyState == 4)
     {
        alert("update");
     }
}

           function getHttpRequest()
           {
               var request=false;
               if(window.XMLHttpRequest)
               {
                   request=new XMLHttpRequest();
               }
               else if(window.ActiveXObject)
               {
                   try
                   {
                       request=new ActiveXObject("Msxml2.XMLHTTP");
                   }
                   catch(e)
                   {
                       try
                       {
                           request=new ActiveXObject("Microsoft.XMLHTTP");
                       }
                       catch(e)
                       {
                           request=false;
                       }
                   }
               }

               return request;
           }

in the function submitVal() it first alert's the salary value as it is(if 1+ then alerts 1+), but when it is posted it just post's value without '+' operator which is needed... is it any problem with query string, as the PHP backend code is working fine...

在函数submitVal()中，它的第一个警告是它的工资值(如果1+然后提醒1+)，但是当它被发布时，它只是post的值，而不需要“+”操作符，这是需要的……对于查询字符串是否有任何问题，因为PHP后端代码运行良好……

2 个解决方案

#1

Use

使用

request.send("sal="+encodeURIComponent(sal));

The + is interpreted as an space on the server side so you need to encode the string first.

+被解释为服务器端的一个空间，因此您需要首先对字符串进行编码。

More info here:

更多信息:

http://xkr.us/articles/javascript/encode-compare/

http://xkr.us/articles/javascript/encode-compare/

#2

You need to encode sal in request.send("sal="+sal). You'll probably find that if sal was equal to "foo & bar", you would end up with just "foo" on the server since the & needs to be encoded too. So:

您需要在request.send(“sal=”+sal)中对sal进行编码。您可能会发现，如果sal等于“foo & bar”，那么服务器上就只剩下“foo”，因为&也需要编码。所以:

request.send("sal=" + encodeURIComponent(sal)); // updated example

However, rather than doing this all by hand, you should think about using a library to do it for you, such as jQuery, then your example would look something like this:

然而，与其手工完成这些工作，不如考虑使用一个库来完成，比如jQuery，那么您的示例应该是这样的:

$.ajax({
   url: "updateSal.php",
   type: "POST",
   data: { sal : $("salary").val() },
   success: function(){
      alert("update");
   }
});

#1

Use

使用

request.send("sal="+encodeURIComponent(sal));