如何通过SNMP将Portchannel映射到接口?

How do I get this result via SNMP?

我如何通过SNMP得到这个结果?

show etherchannel summary

显示etherchannel总结

Group  Port-channel  Protocol    Ports
------+-------------+-----------+-----------------------------------------------
1      Po1(RU)          -        Gi2/3(P)       Gi3/3(P)       
2      Po2(RU)          -        Gi2/4(P)       Gi3/4(P)       
3      Po3(SU)          -        Gi2/2(P)       Gi3/2(P)       
9      Po9(SU)          -        Gi2/12(P)      Gi3/12(P)      
421    Po421(SU)        -        Gi11/1(P)      Gi11/2(P)      Gi11/3(P)      
                             Gi11/4(P)      
422    Po422(SU)        -        Gi11/5(P)      Gi11/6(P)      Gi11/7(P)      
                             Gi11/8(P)      
423    Po423(SU)        -        Te12/1(P)

1 个解决方案

#1

This is a bit late, but researching something similar I came across this Cisco forums post. It reports the following objects in IEEE8023-LAG-MIB:

这有点晚了，但我在研究类似的东西时遇到了思科论坛的帖子。它报告了IEEE8023-LAG-MIB中的以下对象:

IEEE8023-LAG-MIB::dot3adAggPortSelectedAggID.28 = INTEGER: 337
IEEE8023-LAG-MIB::dot3adAggPortSelectedAggID.82 = INTEGER: 337

IEEE8023-LAG-MIB::dot3adAggPortAttachedAggID.28 = INTEGER: 337
IEEE8023-LAG-MIB::dot3adAggPortAttachedAggID.82 = INTEGER: 337

ifName.28 = Gi2/4
ifName.82 = Gi3/10
ifName.337 = Po1

In the same environment the show etherchannel summary command will result in:

在相同的环境中，show etherchannel summary命令将导致:

+------+-------------+-----------+---------------------------------+
| Group|Port-channel |Protocol   | Ports                           |
+------+-------------+-----------+---------------------------------+
|  1   | Po1(SU)     | LACP      | Gi2/4(P)       Gi3/10(P)        |
+------+-------------+-----------+---------------------------------+

#1