I am trying to create friend relationship to all the ids in the list but I am getting an error:
我正在尝试创建列表中所有ID的朋友关系,但我收到一个错误:
y already declared (line 2, column 41 (offset: 64))
"Merge (y:User{id:"21",name:"b"})
Merge (y:User{id:"41",name:"d"})
Merge (y:User{id:"51",name:"e"}) "
^
Neo.ClientError.Statement.InvalidSyntax
I am trying to create a new user with id,name,year and also relationship with existing node at the same time .How can I do it ?Is there any other way also?I really appreciate any help.
我正在尝试创建一个具有id,name,year以及同时与现有节点的关系的新用户。我该怎么做?还有其他任何方式吗?我真的很感激任何帮助。
MATCH (u:User {id:"2"})
Merge (y:User{id:"21",name:"b",year:"2010"})
Merge (y:User{id:"41",name:"d",year:"2011"})
Merge (y:User{id:"51",name:"e",,year:"2013"})
MERGE (u)-[:FRIEND]->(y)
1 个解决方案
#1
Reusing identifier y won't work.
重用标识符y将不起作用。
Try
MATCH (u:User {id:"2"})
unwind [{id:"21",name:"b",year:"2010"},
{id:"41",name:"d",year:"2011"},
{id:"51",name:"e",year:"2013"}] as user
merge (y:User {id: user.id, name: user.name,year:user.year})
MERGE (u)-[:FRIEND]->(y)
#1
Reusing identifier y won't work.
重用标识符y将不起作用。
Try
MATCH (u:User {id:"2"})
unwind [{id:"21",name:"b",year:"2010"},
{id:"41",name:"d",year:"2011"},
{id:"51",name:"e",year:"2013"}] as user
merge (y:User {id: user.id, name: user.name,year:user.year})
MERGE (u)-[:FRIEND]->(y)