I'm trying to figure out how to convert a Jackson object into a JSONObject?
我想弄清楚如何将Jackson对象转换为JSONObject?
What I've tried, however I don't believe this is the correct approach.
我尝试了什么,但我不相信这是正确的方法。
public JSONObject toJSON() throws IOException {
ObjectMapper mapper = new ObjectMapper();
return new JSONObject(mapper.writeValueAsString(new Warnings(warnings)));
}
2 个解决方案
#1
6
Right now, you are serializing your Pojo to a String
, then parsing that String
and converting it into a HashMap
style object in the form of JSONObject
.
现在,您将Pojo序列化为String,然后解析该String并将其转换为JSONObject形式的HashMap样式对象。
This is very inefficient and doesn't accomplish anything of benefit.
这是非常低效的,并没有实现任何好处。
Jackson already provides an ObjectNode
class for interacting with your Pojo as a JSON object. So just convert your object to an ObjectNode
. Here's a working example
Jackson已经提供了一个ObjectNode类,用于与Pojo作为JSON对象进行交互。所以只需将对象转换为ObjectNode即可。这是一个有效的例子
public class Example {
public static void main(String[] args) throws Exception {
Pojo pojo = new Pojo();
pojo.setAge(42);
pojo.setName("Sotirios");
ObjectMapper mapper = new ObjectMapper();
ObjectNode node = mapper.valueToTree(pojo);
System.out.println(node);
}
}
class Pojo {
private String name;
private int age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
Otherwise, the way you are doing it is fine.
否则,你这样做的方式很好。
#2
3
The way you are doing is work fine, because i also use that way to make a JSONobject.
你正在做的工作正常,因为我也使用这种方式来制作一个JSON对象。
here is my code
这是我的代码
public JSONObject getRequestJson(AccountInquiryRequestVO accountInquiryRequestVO) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper mapper = new ObjectMapper();
JSONObject jsonAccountInquiry;
jsonAccountInquiry=new JSONObject(mapper.writeValueAsString(accountInquiryRequestVO));
return jsonAccountInquiry;
}
its working fine for me. but you can always use JsonNode also here is the sample code for that
它对我来说很好。但你可以随时使用JsonNode,这里是示例代码
JsonNode jsonNode=mapper.valueToTree(accountInquiryRequestVO);
its very easy to use.
它非常容易使用。
#1
6
Right now, you are serializing your Pojo to a String
, then parsing that String
and converting it into a HashMap
style object in the form of JSONObject
.
现在,您将Pojo序列化为String,然后解析该String并将其转换为JSONObject形式的HashMap样式对象。
This is very inefficient and doesn't accomplish anything of benefit.
这是非常低效的,并没有实现任何好处。
Jackson already provides an ObjectNode
class for interacting with your Pojo as a JSON object. So just convert your object to an ObjectNode
. Here's a working example
Jackson已经提供了一个ObjectNode类,用于与Pojo作为JSON对象进行交互。所以只需将对象转换为ObjectNode即可。这是一个有效的例子
public class Example {
public static void main(String[] args) throws Exception {
Pojo pojo = new Pojo();
pojo.setAge(42);
pojo.setName("Sotirios");
ObjectMapper mapper = new ObjectMapper();
ObjectNode node = mapper.valueToTree(pojo);
System.out.println(node);
}
}
class Pojo {
private String name;
private int age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
Otherwise, the way you are doing it is fine.
否则,你这样做的方式很好。
#2
3
The way you are doing is work fine, because i also use that way to make a JSONobject.
你正在做的工作正常,因为我也使用这种方式来制作一个JSON对象。
here is my code
这是我的代码
public JSONObject getRequestJson(AccountInquiryRequestVO accountInquiryRequestVO) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper mapper = new ObjectMapper();
JSONObject jsonAccountInquiry;
jsonAccountInquiry=new JSONObject(mapper.writeValueAsString(accountInquiryRequestVO));
return jsonAccountInquiry;
}
its working fine for me. but you can always use JsonNode also here is the sample code for that
它对我来说很好。但你可以随时使用JsonNode,这里是示例代码
JsonNode jsonNode=mapper.valueToTree(accountInquiryRequestVO);
its very easy to use.
它非常容易使用。