接下來繼續講之前沒提到的 copy()
,我們依續之前的列表,來做觀察,看看使用 copy()
有什麼不一樣?
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
names = ["Rogers", "Stark", "Thor", "Loki", "Natasha", "Coulson"]
name2 = names.copy()
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', 'Natasha', 'Coulson']
Process finished with exit code 0
看起來一樣,那接下來我們來修改一下,把 Thor
修改成中文 索爾
,來觀察一下結果
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
names = ["Rogers", "Stark", "Thor", "Loki", "Natasha", "Coulson"]
name2 = names.copy()
print(names)
print(name2)
names[2] = "索爾"
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', 'Natasha', 'Coulson']
['Rogers', 'Stark', '索爾', 'Loki', 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', 'Natasha', 'Coulson']
Process finished with exit code 0
嗯,看起來 names
裡的 Thor
已被修改成中文 索爾
,而 names2
裡的 Thor
則是不變,接下來我們在來做個小變化,在現有的列表中,在插入一個列表
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
name2 = names.copy()
print(names)
print(name2)
names[2] = "索爾"
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', '索爾', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
Process finished with exit code 0
再來如果我想要把剛剛加進去的列表裡的 Jarvis
給變成大寫字母
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
name2 = names.copy()
print(names)
print(name2)
names[2] = "索爾"
names[4][0] = "JARVIS"
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', '索爾', 'Loki', ['JARVIS', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['JARVIS', 'Potts'], 'Natasha', 'Coulson']
Process finished with exit code 0
咦,有發現一個很神奇的問題嗎?為什麼 names裡的JARVIS
跟 names2的JARVIS
是一樣都是大寫
的?但為什麼之前的 names裡的索爾
跟 names2裡的Thor
並沒有被複製過來,這個叫做 淺copy()
,所謂的 淺copy()
就是只複製記憶體裡位置第一層的列表,這原理就有點像是我們之前在一開始所提到的變量,不清楚的可以回頭看一下,或是看下圖我的理解
那如果想要真正全部的複製下來的話,這次我們引入一個 import copy
這個模塊來做完全複製
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
name2 = copy.copy(names)
print(names)
print(name2)
names[2] = "索爾"
names[4][0] = "JARVIS"
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', '索爾', 'Loki', ['JARVIS', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['JARVIS', 'Potts'], 'Natasha', 'Coulson']
Process finished with exit code 0
吚~結果居然跟上次淺copy()
使用的一樣,其實是不一樣的,這個是完全複製下來了,只是我們要改成 深copy()
,修改一下,再觀察一下
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
name2 = copy.deepcopy(names)
print(names)
print(name2)
names[2] = "索爾"
names[4][0] = "JARVIS"
print(names)
print(name2)
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', '索爾', 'Loki', ['JARVIS', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
Process finished with exit code 0
嗯,看起來已經完全獨立複製一份了,但大多數情況下,不需要獨立在複製一份,這個如果當列表夠大時,做了deepcoy()
會很占記憶體空間的,要小心使用。接下來要在試一下把列表做 for循環
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
for i in names:
print(i)
---------------執行結果---------------
Rogers
Stark
Thor
Loki
['Jarvis', 'Potts']
Natasha
Coulson
嗯!很簡單,全部都有打印出來了,那如果想跳著打印列表的話,又該怎麼做?
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
print(names)
print(names[0:-1:2])
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Thor', ['Jarvis', 'Potts']]
Process finished with exit code 0
還記得之前有提到過,在列表裡,0
跟 -1
可以省略,那上面的代碼可不可以在優化一下
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
print(names)
print(names[::2])
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Thor', ['Jarvis', 'Potts'], 'Coulson']
Process finished with exit code 0
如果不跳著打印的話,也可以寫成
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
import copy
names = ["Rogers", "Stark", "Thor", "Loki",["Jarvis", "Potts"], "Natasha", "Coulson"]
print(names)
print(names[:]) # 這個也可以 print(names[::])
---------------執行結果---------------
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
['Rogers', 'Stark', 'Thor', 'Loki', ['Jarvis', 'Potts'], 'Natasha', 'Coulson']
Process finished with exit code 0
但這個就較不常使用,看起來比較不直覺。