[解决办法]Python中使用json.loads解码字符串时出错：ValueError: Expecting property name: line 1 column 2 (char 1)

问题描述

今天在解析字符串中，使用json.loads解码字符串，脚本如下：

import json
string = "{u'lat': 61.190495, u'lng': -149.86884}"
dic = json.loads(string)

运行后报错信息如下：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.6/json/__init__.py", line 307, in loads
return _default_decoder.decode(s)
  File "/usr/lib64/python2.6/json/decoder.py", line 319, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib64/python2.6/json/decoder.py", line 336, in raw_decode
    obj, end = self._scanner.iterscan(s, **kw).next()
  File "/usr/lib64/python2.6/json/scanner.py", line 55, in iterscan
    rval, next_pos = action(m, context)
  File "/usr/lib64/python2.6/json/decoder.py", line 171, in JSONObject
    raise ValueError(errmsg("Expecting property name", s, end))
ValueError: Expecting property name: line 1 column 1 (char 1)

解决方案

1. 替换单引号

类型的错误，就是由于JSON中，标准语法中，不支持单引号，属性或者属性值，都必须是双引号括起来的。

string = string.replace("'", '"')
dic = json.loads(string)

依旧报同样的错误信息，如下：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib64/python2.6/json/__init__.py", line 307, in loads
return _default_decoder.decode(s)
  File "/usr/lib64/python2.6/json/decoder.py", line 319, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib64/python2.6/json/decoder.py", line 336, in raw_decode
    obj, end = self._scanner.iterscan(s, **kw).next()
  File "/usr/lib64/python2.6/json/scanner.py", line 55, in iterscan
    rval, next_pos = action(m, context)
  File "/usr/lib64/python2.6/json/decoder.py", line 171, in JSONObject
    raise ValueError(errmsg("Expecting property name", s, end))
ValueError: Expecting property name: line 1 column 1 (char 1)

2. 替换引号前的u为空，

即去除引号前的u。这种解决编码问题，简单粗暴了点，至于其深入分析，未完待绪。同时也希望各位大神能够提供更好的解决办法。

string = string.replace("u", "") ＃ 这里比较简单，实际中需要用正则条件替换
dic = json.loads(string)

参考网址

http://www.tuicool.com/articles/YBnE3q