本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下:
日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出
使用到函数语法如下
1
2
|
string date (string $Format );
string date (string $Format , int $Time );
|
下面是演示代码
1
2
3
4
5
6
7
8
9
10
11
12
13
14
|
<?php
echo "When this page was loaded,\n" ;
echo 'It was then ' , date ( 'r' ), "\n" ;
echo 'The currend date was ' , date ( 'F j, Y' ), "\n" ;
echo 'The currend date was ' , date ( 'M j, Y' ), "\n" ;
echo 'The currend date was ' , date ( 'm/d/y' ), "\n" ;
echo 'The currend date was the ' , date ( 'jS \o\f M, Y' ), "\n" ;
echo 'The currend time was ' , date ( 'g:i:s A T' ), "\n" ;
echo 'The currend time was ' , date ( 'H:i:s O' ), "\n" ;
echo date ( 'Y' );
date ( 'L' )?( print ' is' ):( print ' is not' );
echo " a leap year\n" ;
echo time ( 'U' ), " seconds had elapsed since January 1, 1970.\n" ;
?>
|
输出结果如下
1
2
3
4
5
6
7
8
9
|
It was then Sat, 26 Dec 2009 07:09:51 +0000
The currend date was December 26, 2009
The currend date was Dec 26, 2009
The currend date was 12/26/09
The currend date was the 26th of Dec, 2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1, 1970.
|
希望本文所述对大家的php程序设计有所帮助。