今天看了看phpcms 写到二级导航时发现点问题,查询导航栏的信息时返回的$r[arrchildid]与自己想象的不符,文档上说是返回子栏目id但是却有些不同。
开始的思路:
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<ul class = "nav navbar-nav" >
<li class = "active" ><a href= "{siteurl($siteid)}" >首页</a></li>
{pc:content action= "category" catid= "0" num= "10" siteid= "$siteid" order= "listorder ASC" }
{loop $data $r }
{ if $r [arrchildid]}
<li class = "dropdown" >
<a href= "{$r[url]}" class = "dropdown-toggle" child= "{$r[arrchildid]}" data-toggle= "dropdown" >{ $r [catname]}<b class = "caret" ></b></a>
<ul class = "dropdown-menu" >
{pc:content action= "category" catid= "$r[catid]" num= "10" siteid= "$siteid" order= "listorder ASC" return = "data2" }
{loop $data2 $v }
<li><a href= "{$v[url]}" >{ $v [catname]}</a></li>
{/loop}
{/pc}
</ul>
</li>
{/ if }
{/loop}
{/pc}
</ul>
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大致思路:查询该文档下是否有子栏目id,如果有则输出二级导航。代码中第5行是检测该栏目下是否有子栏目id,但是我发现当没有子栏目时会返回当前栏目的id导致判断无法达到预期的效果,所以改变思路,代码如下:
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<ul class = "nav navbar-nav" >
<li class = "active" ><a href= "{siteurl($siteid)}" >首页</a></li>
{pc:content action= "category" catid= "0" num= "10" siteid= "$siteid" order= "listorder ASC" }
{loop $data $r }
{ if $r [arrchildid] != $r [catid]}
<li class = "dropdown" >
<a href= "{$r[url]}" class = "dropdown-toggle" child= "{$r[arrchildid]}" data-toggle= "dropdown" >{ $r [catname]}<b class = "caret" ></b></a>
<ul class = "dropdown-menu" >
{pc:content action= "category" catid= "$r[catid]" num= "10" siteid= "$siteid" order= "listorder ASC" return = "data2" }
{loop $data2 $v }
<li><a href= "{$v[url]}" >{ $v [catname]}</a></li>
{/loop}
{/pc}
</ul>
</li>
{ else }
<li><a href= "{$r[url]}" >{ $r [catname]}</a></li>
{/ if }
{/loop}
{/pc}
</ul>
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判断获取到的子栏目id是否等于该栏目id,等于则表示没有子栏目,不等于则表示有子栏目且显示子栏目
以上所述是小编给大家介绍的PHPCMS V9 添加二级导航的思路详解,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!