写爬虫的时候先看看要爬的网页的状态码
print urllib.urlopen(url).getcode()200正常访问
301重定向
404网页不存在
403禁止访问（禁止用一个User-Agent快速多次访问）
**
403解决办法
**
import urllib
import random
my_headers=["Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95 Safari/537.36","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36","Mozilla/5.0 (Windows NT 6.1; WOW64; rv:30.0) Gecko/20100101 Firefox/30.0""Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_2) AppleWebKit/537.75.14 (KHTML, like Gecko) Version/7.0.3 Safari/537.75.14","Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.2; Win64; x64; Trident/6.0)"
def get_content(url):
"""
得到content信息
:param url:
:return: content
"""
randdom_header=random.choice(my_headers)
req = urllib2.Request(url)
req.add_header("User-Agent",randdom_header)
req.add_header("Host","e-hentai.org")
req.add_header("Referer","https://e-hentai.org/lofi")
req.add_header("GET",url)
content=urllib2.urlopen(req).read()
return content原理是用多个User-Agent 不断random，让服务器分辨不清，这样就可以解决403的问题了。