DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference usersRef = rootRef.child("Users");
There's a unique id for each user inside Users child... inside that is the data o
用户内部的每个用户都有一个唯一的id……里面是数据o
1 个解决方案
#1
2
You need to iterate inside the unique id to be able to get the data there:
您需要在唯一id内进行迭代,才能获得那里的数据:
DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference usersRef = rootRef.child("Users");
usersRef.addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot datas: dataSnapshot.getChildren()){
String name=datas.child("name").getValue().toString();
//gets data
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
Example if you have:
如果你有例子:
Users
uniqueid
name: peter
The above will iterate inside the unique id and give you the name "peter"
上面的代码将在唯一id中迭代,并给您命名为“peter”
#1
2
You need to iterate inside the unique id to be able to get the data there:
您需要在唯一id内进行迭代,才能获得那里的数据:
DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference usersRef = rootRef.child("Users");
usersRef.addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot datas: dataSnapshot.getChildren()){
String name=datas.child("name").getValue().toString();
//gets data
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
Example if you have:
如果你有例子:
Users
uniqueid
name: peter
The above will iterate inside the unique id and give you the name "peter"
上面的代码将在唯一id中迭代,并给您命名为“peter”