From within PHP, how can I call an external JSON web service and then decode the returned string?
从PHP中，如何调用外部JSON Web服务然后解码返回的字符串？
For example (pseudo-code):
例如（伪代码）：
<?php
$var jsonStr = json_decode("http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false");
?>
2 个解决方案
#1
19
you almost had it!
你几乎拥有它！
<?php
$jsonObject = json_decode(file_get_contents("http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false"));
?>
#2
0
Nathan has it. You may want to explore the curl library for a more robust HTTP request approach, too.
内森有它。您可能还想探索curl库以获得更强大的HTTP请求方法。
#1
19
you almost had it!
你几乎拥有它！
<?php
$jsonObject = json_decode(file_get_contents("http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false"));
?>
#2
0
Nathan has it. You may want to explore the curl library for a more robust HTTP request approach, too.
内森有它。您可能还想探索curl库以获得更强大的HTTP请求方法。