vb.net Windows 应用程序怎么限制应用程序只运行一个版本

vb.net Windows 应用程序怎么限制应用程序只运行一个版本
就是怎么判断一个应用程序已经打开，不允许再次打开的时候
请指教，谢谢急

10 个解决方案

#1

好象是不行的，支持并行是DONET的特色噢！（我只是随便说说，我也不清楚，呵呵~~~)

#2

http://xml.sz.luohuedu.net/xml/ShowDetail.asp?id=F7810234-04D8-4F9C-B1C7-925919E691FF

摘录自孟子E章：
Public Shared Function RunningInstance() As Process

     Dim current As Process = Process.GetCurrentProcess()

     Dim processes As Process() = Process.GetProcessesByName(current.ProcessName)

     'Loop through the running processes in with the same name

     Dim process As Process

     For Each process In processes

          'Ignore the current process

          If process.Id <> current.Id Then

               'Make sure that the process is running from the exe file.

               If [Assembly].GetExecutingAssembly().Location.Replace("/", "\") = current.MainModule.FileName Then

                    'Return the other process instance.

                    Return process

               End If

          End If

     Next process

     'No other instance was found, return null.

     Return Nothing

End Function 'RunningInstance

#3

Dim mProcs() As System.Diagnostics.Process = System.Diagnostics.Process.GetProcesses
Dim sProc As System.Diagnostics.Process

        For Each sProc In mProcs

            If sProc.ProcessName = "yourapp.exe" Then
                MsgBox("有一个程序已经运行！")
            End If

        Next

#4

楼上，好像"yourapp.exe"，应该是"yourapp",不应该有".exe"吧

#5

怎样才能使当前的程序退出，原来的程序激活（active）?

#6

Public Declare Function SetForegroundWindow Lib "user32" Alias "SetForegroundWindow" (ByVal hwnd As IntPtr) As Integer

Public Sub Main(ByVal args() As String)
        Dim instance As Process = RunningInstance()
        If Not (instance Is Nothing) Then
            MsgBox("此程序已經在運行!", MsgBoxStyle.Information, "提示信息")
            SetForegroundWindow(instance.MainWindowHandle)
            End
        End If
end sub

#7

在你的if语句中加一个end或者application.exit不就退出了吗?

#8

谢谢 landlordh(software)，问题解决了。

#9

EricBai(Eric)，我是说不但要退出，还要把原来的程序激活，只能用api了

#10

？？
你的问题不是说 “就是怎么判断一个应用程序已经打开，不允许再次打开的时候”吗？
如果你第二次运行它就会自动退出阿？我不太明白为什么要激活先前正在运行的程序阿？它不是正在运行中吗？

#1