437. Path Sum III(路径可以任意点开始,任意点结束)

时间:2024-08-10 13:33:38

You are given a binary tree in which each node contains an integer value.

Find the number of paths that sum to a given value.

The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).

The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

Example:

root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8

      10
/ \
5 -3
/ \ \
3 2 11
/ \ \
3 -2 1 Return 3. The paths that sum to 8 are: 1. 5 -> 3
2. 5 -> 2 -> 1
3. -3 -> 11
 class Solution {

     public int pathSum(TreeNode root, int sum) {
if(root==null) return 0;
int res = path(root,sum)+pathSum(root.right,sum)+pathSum(root.left,sum);
return res; } private int path(TreeNode root, int sum) {
int res=0;
if(root==null)
return res ;
if(sum==root.val)
res+=1;
res+=path(root.left,sum-root.val);
res+=path(root.right,sum-root.val);
return res;
} }