Sample Query 1 -
查询样例1 -
SELECT ID,NAME FROM USERS
Sample Query 2 -
查询样例2 -
SELECT Orders.OrderID as ID, Customers.CustomerName as Name, Orders.OrderDate as Date
FROM Orders
INNER JOIN Customers
ON Orders.CustomerID=Customers.CustomerID;
How can I load title headings to an array in PHP? I mean ID,NAME in Query 1 and ID,Name,Date in Query 2
如何在PHP中将标题加载到数组中?我的意思是ID,查询1中的名字和ID,查询2中的名字,日期
This is what I'm trying to do :
这就是我想做的:
I'm creating a PHP function to make HTML table automatically from any given MySQL-Select query
我正在创建一个PHP函数,以便从任何给定的MySQL-Select查询中自动生成HTML表
This where I'm up to now
这就是我现在所做的
function createTable($query) {
$sql_link = Connect_MySQLi_DB();// Database Connection
$sql_link->set_charset("utf8");
$result = $sql_link->query($query);
$headings = array('ID','Name','Date');//I need this array to create automatically
echo '<table>';
echo '<tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
echo '<th>'.$headings[$x].'</th>';
}
echo '<tr>';
while ($row = $result->fetch_object()) {
echo '<tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
echo '<td>' . $row->$headings[$x] . '</td>';
}
echo '<tr>';
}
echo '</table>';
}
So I need to create that $heading array automatically. If I can do that, this function can display any MySQL-Select query as a HTML table
我需要自动创建$heading数组。如果我可以这样做,这个函数可以将任何MySQL-Select查询显示为HTML表
2 个解决方案
#1
4
If you are using mysqli then fetch_fields seems to do the job.
如果您正在使用mysqli,那么fetch_fields似乎可以完成这项工作。
EDIT: Example:
编辑:例如:
$res = $db->query('SELECT A.id,A.a,A.id + B.id AS idd FROM A natural join B');
var_dump($res->fetch_fields());
Returns information about columns A.id, A.a and about the idd column (both tables have other columns). I omitted some fields from the output in order to make it shorter.
返回关于列A的信息。id,一个。a和关于idd列(两个表都有其他列)。为了使输出更短,我省略了输出中的一些字段。
array(3) {
[0]=>
object(stdClass)#3 (13) {
["name"]=>
string(2) "id"
["orgname"]=>
string(2) "id"
["table"]=>
string(1) "A"
["orgtable"]=>
string(1) "A"
// more fields here
}
[1]=>
object(stdClass)#4 (13) {
["name"]=>
string(1) "a"
["orgname"]=>
string(1) "a"
["table"]=>
string(1) "A"
["orgtable"]=>
string(1) "A"
// more fields here
}
[2]=>
object(stdClass)#5 (13) {
["name"]=>
string(3) "idd"
["orgname"]=>
string(0) ""
["table"]=>
string(0) ""
["orgtable"]=>
string(0) ""
// more fields here
}
}
#2
0
Finally this is how I made this function to work (Thanks Hynner for your excellent suggestion),
最后,我是如何让这个功能发挥作用的(谢谢Hynner的建议),
function createTable_from_sql_select_query($query) {
$sql_link = Connect_MySQLi_DB();// Database connection
$sql_link->set_charset("utf8");
$result = $sql_link->query($query);
// Adding Missing array_column Function for Old PHP Versions (<5.5)
if (!function_exists('array_column')) {
function array_column($array, $column) {
$ret = array();
foreach ($array as $row)
$ret[] = $row[$column];
return $ret;
}
}
$headings = json_decode(json_encode($result->fetch_fields()), true);
$headings = array_column($headings, 'name');
$return = '<table>';
$return .= '<thead><tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
$return .= '<th>' . ucwords(str_replace('_', ' ', (strtolower($headings[$x])))) . '</th>';
}
$return .= '</tr></thead><tbody>';
while ($row = $result->fetch_object()) {
$return .= '<tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
$return .= '<td>' . $row->$headings[$x] . '</td>';
}
$return .= '</tr>';
}
$return .= '</tbody></table>';
return $return;
}
Now anyone can convert any SQL select query to a HTML table.
现在任何人都可以将任何SQL select查询转换为HTML表。
#1
4
If you are using mysqli then fetch_fields seems to do the job.
如果您正在使用mysqli,那么fetch_fields似乎可以完成这项工作。
EDIT: Example:
编辑:例如:
$res = $db->query('SELECT A.id,A.a,A.id + B.id AS idd FROM A natural join B');
var_dump($res->fetch_fields());
Returns information about columns A.id, A.a and about the idd column (both tables have other columns). I omitted some fields from the output in order to make it shorter.
返回关于列A的信息。id,一个。a和关于idd列(两个表都有其他列)。为了使输出更短,我省略了输出中的一些字段。
array(3) {
[0]=>
object(stdClass)#3 (13) {
["name"]=>
string(2) "id"
["orgname"]=>
string(2) "id"
["table"]=>
string(1) "A"
["orgtable"]=>
string(1) "A"
// more fields here
}
[1]=>
object(stdClass)#4 (13) {
["name"]=>
string(1) "a"
["orgname"]=>
string(1) "a"
["table"]=>
string(1) "A"
["orgtable"]=>
string(1) "A"
// more fields here
}
[2]=>
object(stdClass)#5 (13) {
["name"]=>
string(3) "idd"
["orgname"]=>
string(0) ""
["table"]=>
string(0) ""
["orgtable"]=>
string(0) ""
// more fields here
}
}
#2
0
Finally this is how I made this function to work (Thanks Hynner for your excellent suggestion),
最后,我是如何让这个功能发挥作用的(谢谢Hynner的建议),
function createTable_from_sql_select_query($query) {
$sql_link = Connect_MySQLi_DB();// Database connection
$sql_link->set_charset("utf8");
$result = $sql_link->query($query);
// Adding Missing array_column Function for Old PHP Versions (<5.5)
if (!function_exists('array_column')) {
function array_column($array, $column) {
$ret = array();
foreach ($array as $row)
$ret[] = $row[$column];
return $ret;
}
}
$headings = json_decode(json_encode($result->fetch_fields()), true);
$headings = array_column($headings, 'name');
$return = '<table>';
$return .= '<thead><tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
$return .= '<th>' . ucwords(str_replace('_', ' ', (strtolower($headings[$x])))) . '</th>';
}
$return .= '</tr></thead><tbody>';
while ($row = $result->fetch_object()) {
$return .= '<tr>';
for ($x = 0; $x <= (count($headings) - 1); $x++) {
$return .= '<td>' . $row->$headings[$x] . '</td>';
}
$return .= '</tr>';
}
$return .= '</tbody></table>';
return $return;
}
Now anyone can convert any SQL select query to a HTML table.
现在任何人都可以将任何SQL select查询转换为HTML表。