剑指offer 二叉搜索树与双向链表

时间：2024-07-20 09:38:02

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剑指offer 二叉搜索树与双向链表

输入一棵二叉搜索树，将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点，只能调整树中结点指针的指向。
剑指offer 二叉搜索树与双向链表
思路，中序遍历压入vector，然后调整
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/*
struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
    TreeNode(int x) :
            val(x), left(NULL), right(NULL) {
    }
};
*/
class Solution {
     
public:
    vector<TreeNode *> m_vector;
    TreeNode* Convert(TreeNode* pRootOfTree)
    {
        if(pRootOfTree==NULL)return NULL;
        printVector(pRootOfTree);
        for(int i=0;i<m_vector.size()-1;i++)
        {
            m_vector[i]->right=m_vector[i+1];
            m_vector[i+1]->left=m_vector[i];
        }
        return m_vector[0];
    }
    void printVector(TreeNode *root)
    {
        if(root->left!=NULL)
            printVector(root->left);
        m_vector.push_back(root);
        if(root->right!=NULL)
            printVector(root->right);
    }
};

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